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Completely factorise the given number. Then group its factors into sets of 3. Take just one representative from each set and multiply these together. The answer is the required cube root.

For example,

1728 = 2*2*2*2*2*2*3*3*3 = (2*2*2)*(2*2*2)*(3*3*3)

So, the cuberoot is = 2 * 2 * 3 = 12

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Wiki User

10y ago

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Wiki User

9y ago

Perfect cubes have prime factors in multiples of 3.

3 x 3 x 3 = 27

2 x 2 x 2 x 5 x 5 x 5 = 1000

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Wiki User

12y ago

a3 + b3 = (a + b)*(a2 - ab + b2) which gives an initial factorisation as shown in the two brackets. Each of these may have further factors.

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Wiki User

9y ago

The prime numbers total the number you started with.

2 x 2 x 3 x 3 = 36

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Q: How can you determine the factors of the sum of two cubes?
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