answersLogoWhite

0

Completely factorise the given number. Then group its factors into sets of 3. Take just one representative from each set and multiply these together. The answer is the required cube root.

For example,

1728 = 2*2*2*2*2*2*3*3*3 = (2*2*2)*(2*2*2)*(3*3*3)

So, the cuberoot is = 2 * 2 * 3 = 12

User Avatar

Wiki User

10y ago

Still curious? Ask our experts.

Chat with our AI personalities

ProfessorProfessor
I will give you the most educated answer.
Chat with Professor
RafaRafa
There's no fun in playing it safe. Why not try something a little unhinged?
Chat with Rafa
EzraEzra
Faith is not about having all the answers, but learning to ask the right questions.
Chat with Ezra
More answers

Perfect cubes have prime factors in multiples of 3.

3 x 3 x 3 = 27

2 x 2 x 2 x 5 x 5 x 5 = 1000

User Avatar

Wiki User

9y ago
User Avatar

a3 + b3 = (a + b)*(a2 - ab + b2) which gives an initial factorisation as shown in the two brackets. Each of these may have further factors.

User Avatar

Wiki User

12y ago
User Avatar

The prime numbers total the number you started with.

2 x 2 x 3 x 3 = 36

User Avatar

Wiki User

9y ago
User Avatar

Add your answer:

Earn +20 pts
Q: How can you determine the factors of the sum of two cubes?
Write your answer...
Submit
Still have questions?
magnify glass
imp