Completely factorise the given number. Then group its factors into sets of 3. Take just one representative from each set and multiply these together. The answer is the required cube root.
For example,
1728 = 2*2*2*2*2*2*3*3*3 = (2*2*2)*(2*2*2)*(3*3*3)
So, the cuberoot is = 2 * 2 * 3 = 12
78
24 and 16 are factors of 48
8 and 5
a3 + b3 = (a + b)(a2 - ab + b2) a3 - b3 = (a - b)(a2 + ab + b2)
You can't have the sum of one thing. Factors multiply to get a product. 7 x 9 = 63. If you add those two numbers, you will get a sum. 7 + 9 = 16
The sum of two cubes can be factored as below.a3 + b3 = (a + b)(a2 - ab + b2)
a3 + b3
That means that you calculate the cubes of two numbers, and then either add or subtract them.
1
The sum of their squares is 10.
50%
1
Sum and difference of two cubes is factored this way : a3 + b3 = (a + b)(a2 - ab + b2) a3 - b3 = (a - b)(a2 + ab + b2)
You get the sum of 11 two ways; 5,6 and 6,5.
23 = 8, 33 = 27. Sum 35, difference 19...
a3+ b3 = (a + b)(a2 - ab + b2)
According to Ramanujan, it's the lowest number that can be expressed in two different ways as the sum of two cubes (the cubes of 12 and 1; the cubes of 10 and 9). It 's the answer.