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Kailyn Larson

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3y ago
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11y ago

That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (5 plus or minus the square root of 73) divided by 12

x = 1.128666978776461

x = -0.2953336454431275

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12y ago

36X2 - 64Y2

4(9X2 - 16Y2)

=============best I can see

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13y ago

(6y+1)(6y-1)

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13y ago

(7 + 6y)(7 - 6y)

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Q: How can you factor 36y2 - 1?
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How do you factor 36y2 - 1?

(6y + 1)(6y - 1)


Factor the following 36y2 - 1?

36y^2 - 1 = (6y - 1)(6y + 1)


Factor the polynomial 25x2-36y2?

25x2 - 36y2 = ( 5x + 6y ) ( 5x - 6y )


What is the answer to X2 plus 13xy plus 36y2?

If by "What is the answer to", you mean "How do you factor", then we can solve it as follows: x2 + 13xy + 36y2 = x2 + 4xy + 9xy + 36y2 = x(x + 4y) + 9y(x + 4y) = (x + 9y)(x + 4y)


How do you factor 16x2 plus 48xy plus 36y2?

4(2x + 3y)(2x + 3y)


How do you isolate x2 10x2 - 36y2 equals 100?

x2 − 36y2


How do you factor 36y2-25?

Here's a handy gadget that should be in your toolbox if you're working with algebra: The difference of the squares of 2 numbers = (Sum of the numbers) times (difference of the numbers) 36y2 is the square of 6y, and 25 is the square of 5. So ( 36y2 - 25 ) = ( 6y + 5 ) ( 6y - 5 )


How do you factor 250 x cubed minus 432 x cubed?

2(5x - 6y)(25x2 + 30xy + 36y2)


How do you factor the following two equations 3x2 - 10xy plus 3y2 36y2 - 121?

(3x - y)(x - 3y) (6y - 11)(6y + 11)


How do you factor the binomial 25x2-36y2?

25x2 - 36y2If you notice that 25 and 36 are perfect squares, you know that your answer would be like the following: (5_ + 6_)(5_ - 6_)because 25x2 - 36y2 is a perfect square binomial, so their square roots fit that way. This only works if the middle sign is minus.From there, you just plug in the x's and y's to get:(5x + 6y)(5x - 6y)


Which choice shows 10x2 - 36y2 equals 100 in isolated form?

y=12


10x2- 36y2 equals 100 isolate x2?

x2 = 18y2/5 + 10 Or if you want to isolate x: x = ± √(18y2/5 + 10)