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Divide the entire equation by 9. (9x2 + 27x + 18)/9 would then be 9(x2 + 3x +2)

The factors of this equation would be 9(x + 1)(x + 2)

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Q: How do you factor 9x squared plus 27x plus 18?

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5x squared plus 33x plus 18 = (5x + 3)(x + 6) x = -6, -3/5

9(3x + 1)(3x - 2)

9(x2 - 2)

A factor is like this. Original :x^2 + 7x - 18 (( x squared plus six x minus 18) Factored: (x+9)(x-2) ((x plus nine times x minus two))

0 = 2m^2 - 2m + 36 0 = 2(m^2 - m + 18) 0 = m^2 - m + 18

Related questions

4x + 27x + 18 = 0 31x + 18= 0 31x + 18 - 18= 0 - 18 31x = -18 31x / 31 = -18 / 31 x = -.58

5x squared plus 33x plus 18 = (5x + 3)(x + 6) x = -6, -3/5

If that's -18y2, the answer is (3x - 2y)(x + 9y)

Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)

12 squared plus 18 squared is equal to 468.

9(3x + 1)(3x - 2)

2(4x - 3)(x + 3)

(x2 + 7x - 18) = (x + 9)(x - 2)

b= 10

5x2 - 27x - 18 = (5x + 3)(x - 6)

6(3r^2 - 14r + 3) and (2c + 1)(c - 9)

The given expression can be simplified to: 3X squared +27

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