Best Answer

9x2 + 12x + 4

= 9x2 + 6x + 6x + 4

= 3x(3x + 2) + 2(3x + 2)

= (3x + 2)(3x + 2)

= (3x + 2)2

Study guides

☆☆

Q: Factor 9x2 plus 12x plus 4?

Write your answer...

Submit

Still have questions?

Continue Learning about Basic Math

2(3x^2 + 6x + 2)

(x - 8)(x - 4)

The expression can be factored as -12x + 32y -16z = 4(-3x + 8y - 4z) but a slightly improved presentation would be to extract -4 from the original expression. So, -12x + 32y -16z = -4(3x - 8y + 4z)

While it is possible to factor 3x2 from both of these and get 3x2(4 - 1), it's a lot easier to subtract 3x2 from 12x2 and get 9x2

If the question could more exactly be phrased as, "What is the value of x when 9x2 - 16 = 0", the answer is, x = 4 or -4. This answer can be found by factoring 9x2 - 16 into (3x + 4)(3x - 4) and setting each factor equal to zero.

Related questions

It is: 122-4*(9*-2) = 216

9x2...I guess that means 9x squared ? The problem: 9x(squared)+12x+4 Here's the answer: (3x+2)(3x+2) or even more simplified: (3x+2) squared

There's a chance this was notated incorrectly. It looks like it wants to be some combination of 3x and 2. 9x2 + 12x + 4 = (3x + 2)(3x + 2) or (3x + 2)2 -9x2 - 12x - 4 = -(3x + 2)2 9x2 - 12x + 4 = (3x - 2)2 -9x2 + 12x - 4 = -(3x - 2)2

3x3+12x = 3x(x2+4)

(3x + 4)(3x + 4)

x2 + 12x + 32 = (x + 8)(x + 4)

(x + 4)(x + 8)

x2 + 12x + 32 = (x + 4)(x + 8)

2(3x^2 + 6x + 2)

4(x + 2)(x + 1)

(3x + 5)(3x^2 + 4)

2(x + 4)(x + 2)