9x2 + 12x + 4
= 9x2 + 6x + 6x + 4
= 3x(3x + 2) + 2(3x + 2)
= (3x + 2)(3x + 2)
= (3x + 2)2
There's a chance this was notated incorrectly. It looks like it wants to be some combination of 3x and 2. 9x2 + 12x + 4 = (3x + 2)(3x + 2) or (3x + 2)2 -9x2 - 12x - 4 = -(3x + 2)2 9x2 - 12x + 4 = (3x - 2)2 -9x2 + 12x - 4 = -(3x - 2)2
It is: 122-4*(9*-2) = 216
9x2...I guess that means 9x squared ? The problem: 9x(squared)+12x+4 Here's the answer: (3x+2)(3x+2) or even more simplified: (3x+2) squared
3x3+12x = 3x(x2+4)
(3x + 4)(3x + 4)
x2 + 12x + 32 = (x + 8)(x + 4)
(x + 4)(x + 8)
x2 + 12x + 32 = (x + 4)(x + 8)
4(x + 2)(x + 1)
2(3x^2 + 6x + 2)
(3x + 5)(3x^2 + 4)
2(x + 4)(x + 2)