(X minus the cube root of fifteen) times (x squared plus the cube root of fifteen plus fifteen to the two thirds power)
In Winter - Cold, about minus 0 to minus 40 Celsius In Spring - Wet, about minus 0 to plus 15 Celsius In Summer - Hot, plus 20 to plus 40 Celsius In Autumn - Wet, plus 15 to minus 0 Celsius
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (-615 plus or minus 15 times the square root of 3281) divided by 2. x = 122.10010474859058 x = -737.10010474859058
5(x + 3)(x + 1)
15(p + 4)
3x^2 -14x +15 = (3x-5)(x-3)
(x - 5)(x + 3)
x - 3
x - 5
15x2 - 30x -720 = 15(x - 8)(x + 6).
It is impossible but if it were x squared plus 2x minus 15 the equation would be (x+5) (x-3) with x being equal to either -5 or 3. If the original problem was x squared minus 2x minus 15 the equation would be (x-5)(x+3) and x would be equal to either 5 or -3
You have to experiment with different factors of 2, and different factors of 15. In this case, 2x2 - 11x + 15 = (2x - 5) (x - 3)
Without any parenthesis is: 92 - 2 * 15 + 16 - 8 = 59
(x + 15)(x - 3)
2s2+7s-15 = (2s-3)(s+5) when factored
What about it? Factorise it?
it is prime. it cannot factor out.