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The rules of divisibility tell you that 63 is divisible by 1 (because all integers are), 3 (because its digits total a multiple of 3) and 9 (because its digits total a multiple of 9)

Dividing those numbers into 63 gives you the other three (63, 21 and 7)

(1, 3, 7, 9, 21, 63)

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11y ago

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Q: How do you find all the factors of 63?
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