As a product of its prime factors: 2*2*3*11 = 132
In exponent terms: 22*5*132 = 3380
Well, isn't that a lovely question! To find the highest common multiple of 66, 121, and 132, we first need to find the multiples of each number. Then, we look for the largest number that is a multiple of all three. It's like finding a happy little tree among the forest - just take your time and enjoy the process!
132 = 2 * 2 * 3 * 11 = 22 * 3 * 11198 = 2 * 3 * 3 * 11 = 2 * 32 * 11
how am i supposed to kno do u think i am like magic or something ????
prime factorization of 132=2^2*3*11
2 x 2 x 3 x 11 = 132
Prime factorization of 132 = 2 x 2 x 3 x 11 = 11x3x22
The prime factors of 132 are: 132 = 2 * 2 * 3 * 11
The prime factorization of 132 is 2 x 2 x 3 x 112 x 2 x 3 x 11 = 132
132
To find the Least Common Multiple (LCM) of 22, 132, and 253, we first need to find the prime factorization of each number. The prime factorization of 22 is 2 x 11, the prime factorization of 132 is 2^2 x 3 x 11, and the prime factorization of 253 is 11 x 23. To find the LCM, we take the highest power of each prime factor that appears in the factorizations, which gives us 2^2 x 3 x 11 x 23 = 3036. Therefore, the LCM of 22, 132, and 253 is 3036.
2 x 2 x 3 x 11 = 132
Use a factor tree. 132 66,2 33,2,2 11,3,2,2
You multiply them together to find out. 132
As a product of its prime factors: 2*2*3*11 = 132
22 x 3 x 11 = 132