Since 160 = 16 x 10 = 16 x 2 x 5, if you know the factors of 16, then just tack on the [2 x 5] factors, to have all the factors of 160.
Since 80 is a factor of 160, all of its factors are common.
As a product of its prime factors: 2*3*3*3 = 54 Or: 47+7 = 54
30, 42, 66, 78, 102, 105, 114, 138 all have exactly three distinct prime factors.
The Highest Common Factor (HCF) of 120 and 160 is the largest positive integer that divides both 120 and 160 without leaving a remainder. To find the HCF, we need to determine the common factors of 120 and 160. The factors of 120 are 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, and 120. The factors of 160 are 1, 2, 4, 5, 8, 10, 16, 20, 32, 40, 80, and 160. The largest common factor between 120 and 160 is 40. Therefore, the HCF of 120 and 160 is 40.
33/160 The factors of '33' are '3' & 11' The factors of 160 are 2,4,8,10,16,32,40, & 80. There are no common factors, so the fraction 33/160 cannot be reduced.
105
The common factors of 160 and 365 are: 1 and 5
105
Twelve factors.
I found 105,63 and 27
How about 30 or 105
The 12 factors of 160 are 1, 2, 4, 5, 8, 10, 16, 20, 32, 40, 80, and 160.
Well, isn't that just a happy little question! To write 160 as a product of its prime factors, we can express it as 2^5 * 5. In index form, this would be written as 2^5 * 5^1. Just remember, there are no mistakes, only happy little accidents in math!
Since 160 = 16 x 10 = 16 x 2 x 5, if you know the factors of 16, then just tack on the [2 x 5] factors, to have all the factors of 160.
249,480 has 160 factors.
The prime factors of 160 are 2, 2, 2, 2, 2, and 5. The prime factors of 195 are 3, 5, and 13. The prime factors they have in common are a single 5, so 5 is the greatest common factor.