1 x 144, 2 x 72, 3 x 48, 4 x 36, 6 x 24, 8 x 18, 9 x 16, 12 x 12.
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Since 160 = 16 x 10 = 16 x 2 x 5, if you know the factors of 16, then just tack on the [2 x 5] factors, to have all the factors of 160.
Since 80 is a factor of 160, all of its factors are common.
As a product of its prime factors: 2*3*3*3 = 54 Or: 47+7 = 54
30, 42, 66, 78, 102, 105, 114, 138 all have exactly three distinct prime factors.
The Highest Common Factor (HCF) of 120 and 160 is the largest positive integer that divides both 120 and 160 without leaving a remainder. To find the HCF, we need to determine the common factors of 120 and 160. The factors of 120 are 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, and 120. The factors of 160 are 1, 2, 4, 5, 8, 10, 16, 20, 32, 40, 80, and 160. The largest common factor between 120 and 160 is 40. Therefore, the HCF of 120 and 160 is 40.