Let there be a line A-----------B. From A draw a line D upwards. From B draw a line C upwards.
D C
Z
A B P
Draw an arbitrary point Z and connect it with zdc and zab. Let interior angles ADC= 1 and BCD=2. Exterior angles ZAD=x and CBP(another arbitrary poion)=y. Let a and b be other two interior angles with point A and B.
Now in triangle ZBC
angle Z+b+2=180. Also b+y=180
y=Z+2--------(L)
In triangle ZAD, Z+x+180-1=180; Z+x=1 or x=1-z--------(M)
Adding L and M x+y=1+2
The relationship is that they are supplementary angles because angles on a straight line add up to 180 degrees
squares and hexagons are both convex polygons (meaning their angles dont point inwards) and both have an even amount of sides/vertices
108 degrees The sum of all interior angles of a polygon is equal to the following: 180n-360, where n is the number of sides. For n=5, the total of all of the angles is 180*5-360=900-360=540. Since every angle in a regular polygon, each interior angle of a regular pentagon is 540/5=108 degrees.
In mathematical terms, a diamond shape is often referred to as a "rhombus." A rhombus is a type of quadrilateral where all four sides are of equal length, and opposite angles are equal. Additionally, the diagonals of a rhombus bisect each other at right angles.
Yes.Although the definition of a parallelogram is "a quadrilateral with both pairs of opposite sides parallel", the only way for a quadrilateral to include opposite sides of equal length is if the included angles are the same, and hence the sides are parallel.(Hint : draw a diagonal to a parallelogram. You can show that one of the two triangles formed is the mirror image of the other, which immmediately proves that each pair of opposite sides is equal.)
A quadrilateral.
-- The sum of exterior angles of any polygon is 360 degrees.-- The sum of interior angles of any quadrilateral, no matter what shape, is 360 degrees.-- 360 + 360 = 720 degrees.
I'm not sure if you mean interior or exterior angles, so I'll give you an answer for both.For interior angles:The sum of the measures of the *interior* angles of a quadrilateral is always 360 degrees. To understand why this is true, recall that the sum of the interior angles of a triangle is 180 degrees. Now, in any quadrilateral, we can draw a diagonal, splitting it into two triangles.So, the sum of the interior angles of the quadrilateral will be the sum of all of the interior angles of the two triangles, in other words, 2x180.In general, an n-gon can be divided into n-2 triangles, so the sum of the interior angles of an n-gon is 180x(n - 2) = 180xn - 360For exterior angles:The sum of the exterior angles of any closed, convex figure will be 360 degrees. So, if the quadrilateral is convex (isn't bent inwards) the sum of the exterior angles will be 360 as well.
A 4 sided quadrilateral has interior angles that add up to 360 degrees and its exterior angles add up to 360 degrees
I don't know if you'd say they "have to", but they always do. The interior angles do, and so do the exterior angles.
There are 4 interior angles in a quadrilateral
The 4 exterior angles of any quadrilateral add uo to 360 degrees
The sum of the interior angles of a quadrilateral is 360 degrees (not 180). The sum of the exterior angles is also 360 degrees. Whether the quadrilateral is convex or concave is not relevant.
360 degress which is the same as the sum of the interior angles of a quadrilateral. 360 + 8 x 180 = 1800°
The interior angles sum to 360 degrees; the exterior angles also sum to 360 degrees.
The sum of exterior angles in a Quadrilateral, and indeed in any concave polygon is 360 degrees.
The sum of the exterior angles of a polygon equals 360.Quadrilateral has 4 exterior angles.360/4=90 for a regular quadrilateral.