The acceleration of an object that falls from a certain height does not depend on its mass, in an ideal condition with no air resistance.
The value of acceleration is the acceleration due to gravity, which is 9.81 m s-2.
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However, in this case, air resistance is going to matter. 12000 feet is high enough for the person to accelerate to what we call terminal velocity. Terminal velocity is the velocity where the force of acceleration due to gravity (9.81 m s-2) is matched by the air resistance. That velocity varies, depending on the outline shape of the person, and is typically around 200 km/h or 125 mph. That will be the velocity of the fall.
12000 feet
9.8 meters per second squared. So the longer they are in the air, they will fall faster by each second.
Density at 12,000 feet (or 3658 m), is 0.05302 lbm/ft^3 (or 0.8491 kg/m^3).
~230 Feet Tall, though the free-fall distance is about 200 feet
They would not be the same thing. 4.9 feet would be 58.8 inches and 4 feet 9 inches would be 57 inches.
1.5 sec
36000 ' = 12000 yd36000 ' = 12000 yd36000 ' = 12000 yd36000 ' = 12000 yd36000 ' = 12000 yd36000 ' = 12000 yd
Too fast!
12000 inches = 1000 feet since 12 inches = 1 foot
200mph
3657.6 meters
12,000 feet is 3,657.6 meters.
It depends on height of the bridge. If you fall ten feet you don't have time to build up speed rather than if you were on a 100,000 foot bridge.
The radius 1,910 feet.
39370.078740157480315 feet (being too precise)
1 ft = 0.3048 meters (exact conversion ratio, this is a good one to memorize).(12000 ft) * (0.3048 m/ft) = 3657.6 m
3.66