7 x 13 = 91. Therefore, 91 is a common multiple of 7 and 13, because both 7 and 13 are factors of the multiple, 91.There are infinitely many common multiples of 7 and 13: specifically, these consist of multiples of 91.
Not AllTo find out if all numbers that have 5 as a factor have 2 as a factor, you can list the multiples of each. 5's multiples are 5, 10, 15, 20...2's multiples are 2, 4, 6, 8, 10, 12, 14, 16, 18, 20...5 and 15 are multiples of 5, but not 2, so all numbers that have 5 as a factor DO NOT have 2 as a factor.It is not really necessary to write that all out because the fact that 5 is an odd number and 2 is only a factor of even numbers indicates that all numbers that have 5 as a factor would not have 2 as a factor. Only the multiples of 5 that are even have 2 as a factor also.
13, 26, 39, 52, 65, 78, 91, 104, 117, 130, 143 . . .
91
What you are looking for is the Common Factor/Divisor. In this case, because both 7 and 13 are prime numbers, the answer is 1. But this is often considered a trivial factor since it is a common factor of all integers.
91, 182, 273, 364, and all others of the infinite number of multiples of 91 are divisible by 91.
An infinite number of multiples of 91 can be divided by 91.
the multiples of 91 are 1,7,13 and 91. ps. 91 not a prime number its a conditional
All of its multiples can.There are an infinite number of them.A few examples are:9118227363771,799
91, 182, 273 and so on.
All multiples of 91, which is an infinite number.
7 x 13 = 91. Therefore, 91 is a common multiple of 7 and 13, because both 7 and 13 are factors of the multiple, 91.There are infinitely many common multiples of 7 and 13: specifically, these consist of multiples of 91.
Assuming you meant 'which numbers are multiples of 7'..... 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91 & 98 are all the multiples of seven less than 100
91,182,273,364,455,546,637,728,819,910
91
91
Multiples of 91:91 / 7 = 1391 / 13 = 77,13,91There really aren't any tricks here, just trial and errorSome multiples of 156:Because we already found the multiples of 91, and we know 156 isn't divisible by 91, let's try 13 (once again trial and error)156/13 = 122,12,13,156The answer is 13.