5 of them.
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7 x 13 = 91. Therefore, 91 is a common multiple of 7 and 13, because both 7 and 13 are factors of the multiple, 91.There are infinitely many common multiples of 7 and 13: specifically, these consist of multiples of 91.
The multiples of 13 are numbers that can be divided by 13 without leaving a remainder. The multiples of 13 are: 13, 26, 39, 52, 65, 78, 91, 104, 117, and so on. The multiples of 7 are numbers that can be divided by 7 without leaving a remainder. The multiples of 7 are: 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, and so on.
Not AllTo find out if all numbers that have 5 as a factor have 2 as a factor, you can list the multiples of each. 5's multiples are 5, 10, 15, 20...2's multiples are 2, 4, 6, 8, 10, 12, 14, 16, 18, 20...5 and 15 are multiples of 5, but not 2, so all numbers that have 5 as a factor DO NOT have 2 as a factor.It is not really necessary to write that all out because the fact that 5 is an odd number and 2 is only a factor of even numbers indicates that all numbers that have 5 as a factor would not have 2 as a factor. Only the multiples of 5 that are even have 2 as a factor also.
13, 26, 39, 52, 65, 78, 91, 104, 117, 130, 143 . . .
91