Method 1:
Completing the Square
x2 - 12x + 16 = 0
x2 - 12x + 16 + 20 = 0 + 20
x2 - 12x + 36 = 20
(x - 6)2 = 20
√((x - 6)2) = ±√(20)
√((x - 6)2) = ±√(2*2*5)
x - 6 = ±2√(5)
x - 6 + 6 = 6 ±2√(5)
x - 6 + 6 = 6 ±2√(5)
x = 6 ± 2√(5)
Method 2:
Quadratic Formula
Standard form of a quadratic equation:
ax2 + bx + c = 0
x2 - 12x + 16 = 0
a = 1
b = -12
c = 16
x = (-b ± √(b2 - 4ac))/ 2a
x = (-(-12) ± √((-12)2 - 4(1)(16)))/ 2(1)
x = ((12) ± √(144 - 64))/ 2
x = (12 ± √(80))/ 2
x = (12 ± 4√(5))/ 2
x = 12/2 ± (4/2)√(5)
x = 6 ± 2√(5)
If you mean t(t+7) = 4(3+2t), then it is factored. If you meant solve for 't', then the solution is t = t2 - 12.
This is a hyperbola. It is best approached using Fermat's factorisation method. Seefermat-s-factorization-methodor google wikepedia. I don't know of any faster approach.
(p + 12)(p - 7) p = 7, -12
Assuming the question is written as: x2+11x-12 This would factor to: (x+12)(x-1)
4 and 3 are factors of 12.
12 + 5 equals...
a= -0.8
-0.5
If n + 7 = 12, then n = 12 - 7
In math problems without punctuation such as brackets, the standard convention in to solve from left to right. Therefore, you would solve the problem 15-3 times 4 plus nine like by three actions. 15-3 equals 12; 12 times 4 equals 48; 48 plus 9 equals 57.
-12=m+4 -16=m
-2x2 + 9x - 12 = 0Then apply the quadratic formula.
7x = 3x - 12 4x=-12 x=-3
A + 9 = 21 A = 21 - 9 A = 12
X=6
X = 12
5 plus 25 equals 60. Need to solve for 5 plus 25 equals ?: 2 plus 10 equals 24 is equivalent to 2 × (1 plus 5) equals 2 × (12); and 3 plus 15 equals 36 is equivalent to 3 ×(1 plus 5) equals 3 × (12); thus 5 plus 25 equals ? is equivalent to 5 × (1 plus 5) equals 5 × (12); thus ? = 5 × 12 = 60.