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Write 4 to the second power times 5 to the thrid power as a product of prime factors without using exponents?
2 x 2 x 2 x 2 x 5 x 5 x 5
How do you write down the prime factorization without exponents?
Write them out. 2 x 2 x 2 x 3 x 3 x 5 x 5 x 5 = 9000
What is the prime factorization of 9 and write with exponents?
Prime Factorization of 9 is 3x3=9 So it is 3 to the second power
How do you write x(x-2) 3(2-x) as a product of binomial?
To write ( x(x-2) + 3(2-x) ) as a product of binomials, first simplify the expression. Notice that ( 2 - x ) can be rewritten as ( -(x - 2) ), so ( 3(2-x) = -3(x-2) ). Combining the terms, we have ( x(x-2) - 3(x-2) = (x-2)(x-3) ). Thus, the expression can be factored as ( (x-2)(x-3) ).
How do you write the prime factorization of 100 using exponents?
List each prime factor in a multiplication statement, then raise them to a power however many times are necessary to make the number. E.g. the prime factors of 120 are 2, 3 and 5. Listing these in a multiplication statement is 2 x 3 x 5. Giving each a power so the product will equal the number makes the statement 23 x 3 x 5.
