The LCM is 504
(1+2+3)*4 = 6*4 = 24
No.To check for divisibility by 6, the number must be divisible by both 2 and 3:To check divisibility by 2: if the number is even (last digit is one of 0, 2, 4, 6, 8) then the number is divisible by 2. Last digit of 56 is 6 which is even so 56 is divisible by 2.To check divisibility by 3: if the sum of the digits is divisible by 3, then so is the original number; the test can be repeated on the sum, so if it is repeated until a single digit remains, the original number is divisible by 3 if this single digit is 3, 6 or 9.For 56: 5 + 6 = 11 → 11: 1 + 1 = 2; 2 is not one of 3, 6 or 9, thus 56 is not divisible by 3.As 56 is not divisible by both 2 and 3, it is not divisible by 6.No.We can ask ourselves what are the multiples of six?6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, and so on.We see that 56 is not in this set of numbers. So it's not a multiple of six. We can also see that each of these numbers can be divided by six. So a quicker way of deciding would be to try to divide 56 by 6. 56/6 = 9-4/6 or 9-2/3. It doesn't divide evenly so again, 56 is not a multiple of 6.no60 = 6 x 1054 = 6 x 9so 56 is not a multiple of 6
The multiples of 56 are in infinite set that begins 56, 112, 168, 224, 280, 336, 392, 448, 504, 560, 616, and so on. The multiples of 56 are any number which can be obtained by multiplying 56 by any other number .... there are, literally, an infinite number of these - for instance 56 x 12,345 = 691,320Starting from 1x56 they are:56,112,168,224,280,336,392,448,504,560,616,672, etc.
56
The answer is 7. Seven squared is forty nine. 49 plus 7 equals 56.
7 Or -8
7
56 is composite number.
56
18 and 38
18 and 38
X^2 + x = 56 ie x(x +1) = 56 so x is 7
That means to multiply the number by itself, that is, 56 x 56.
72 + 7 = 56
12 and 56
"7" is the number because its square root is "49" & 49+7=56