Yes: 109 is divisible by itself and one because it is a prime number.
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The product of the prime factors of 218 is 218. The prime factors of 218 are 2 and 109, making their product 2 x 109 = 218! I wouldn't expect it to be otherwise: the product of the prime factors of a number equal the number.
Not evenly, the answer is roughly 0.003
Prime factorization of 109 = 1 * 109
109 and 1 is the only factor pair for 109.
1, 2, 41, 82, 109, 218, 4469, 8938