Well, honey, 678 is divisible by 1, 2, 3, 6, 113, 226, 339, and 678. So, take your pick! Just don't come crying to me if you pick the wrong one and end up with a remainder.
All numbers are divisible by 2145. Any element of the set of numbers of the form 2145*k where k is an integer is evenly divisible.
113 is already prime. No factorization.
They are one and itself because 113 is a prime number
Itself and one because 113 is a prime number
113 is a prime number. It is divisible only by 1 and itself.
No.
yes 113/3=37.666667
5, 113.
226 / 2 = 113
Just 1.
Yes but it will have a remainder of 1
It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.
Not evenly because there will be a remainder of 1
The number 113 is a prime number. It is not divisible by any number except 1 and itself.
By these factors: 1, 3, 9, 113, 339, 1017.
109 is divisble by 9