No.
Any number ending in 5 is a multiple of 5.
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345/\3115....../\....5 23
As a product of its prime factors: 3*5*23 = 345
392 = 2 x 2 x 2 x 7 x 7 OR 2^3 x 7^2
234 = 2 x 3 x 3 x 13 345 = 3 x 5 x 23
The factors of 1725 are: 1 3 5 15 23 25 69 75 115 345 575 1725. The prime factors are: 3, 5, 23