No. 35 is divisible by: 1, 5, 7, 35.
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∙ 2013-07-09 13:00:57Yes: 280 / 8 = 35
Yes because 280/7 = 40 and 280/8 = 35
Neither is divisible by 8.
Yes because 280 is divisible by 35.
Every number is divisible by any non-zero number. It is evenly divisible by 8.
Yes: 280 / 8 = 35
280/5 = 56 280/8 = 35 Therefore, 280 is divisible by both 5 and 8.
35 is not divisible by 3.
Yes because 280/7 = 40 and 280/8 = 35
35 is divisible by 5 because any number that ends in 5 is divisible by 5.
No. To be divisible by 6 the number must be divisible by both 2 and 3. To be divisible by 2, the last digit of the number must be even (ie one of {0, 2, 4, 6, 8}). The last digit of 35 is 5 which is not even and so 35 is not divisible by 2. To be divisible by 3, sum the digits of the number and if this sum is divisible by 3 then so is the original number. As the test can be applied to the sum, repeatedly summing the digits of the sums until a single digit remains, then the original number is divisible by 3 only if this single digit is one of {3, 6, 9}. For 35 3 + 5 = 8 which is not divisible by 3 (nor is is one of {3, 6, 9}, thus 35 is not divisible by 3. As 35 is not divisible by both 2 and 3 (in fact it is divisible by neither 2 nor 3) it is not divisible by 6.
The numbers that are divisible by 35 are infinite. The first four are: 35, 70, 105, 140 . . .
Yes, evenly 5 times. 35 is also divisible by: 1, 5 and 35.
35
There are no such numbers. The only number in the range that is divisible by 35 is 70 and that is not divisible by 9.
753 is not divisible by 35. The factors of 753 are 1, 3, 251, 753.
No.