No. 35 is divisible by: 1, 5, 7, 35.
Yes because 280 is divisible by 35.
Yes because 280/7 = 40 and 280/8 = 35
Any element of the set of numbers of the form 60*k, where k is an integer, is evenly divisible.
3 is not divisible by 126. 126 is divisible by 3.
280
280/5 = 56 280/8 = 35 Therefore, 280 is divisible by both 5 and 8.
No. 35 is divisible by: 1, 5, 7, 35.
No.
2
Yes - 280/4 = 70
Yes because 280 is divisible by 35.
All common multiples of 7, 10 and 8 are divisible by them. The lowest common multiple of them is 280, so all multiples of 280 are divisible by them, namely 280, 560, 840, 1120, ...
280 is divisible by: 1, 2, 4, 5, 7, 8, 10, 14, 20, 28, 35, 40, 56, 70, 140, 280.
Yes because 280/7 = 40 and 280/8 = 35
Any of its factors
Any element of the set of numbers of the form 60*k, where k is an integer, is evenly divisible.