It's divisible by both (240 times for 9, 270 times for 8)
The number 2,340 can be divided by the number 9 260 times.
Using the tests for divisibility:Divisible by 3:Add the digits and if the sum is divisible by 3, so is the original number: 6 + 8 + 4 = 18 which is divisible by 3, so 684 is divisible by 3Divisible by 6:Number is divisible by 2 and 3: Divisible by 2:If the number is even (last digit divisible by 2), then the whole number is divisible by 2. 684 is even so 684 is divisible by 2.Divisible by 3:Already shown above to be divisible by 3. 684 is divisible by both 2 & 3 so 684 is divisible by 6Divisible by 9:Add the digits and if the sum is divisible by 9, so is the original number: 6 + 8 + 4 = 18 which is divisible by 9, so 684 is divisible by 9Thus 684 is divisible by all 3, 6 & 9.
It is divisible by 8 because 202008/8 = 25251 But divided by 9 it will leave a remainder ----------------------- To test if a number is divisible by 8 add the ones digit to twice the tens digit to 4 times the hundreds digit; if this sum is divisible by 8 then so is the original number. By repeating the test on the sum until a single digit remains, only if this single digit is 8 is the original number divisible by 8, otherwise it gives the remainder when divided by 8 (except if it is 9, in which case the remainder is 1 - the excess of 9 over 8). For 202008: ones_digit + 2 × tens_digit + 4 × hundreds_digit = 8 + 2 × 0 + 4 × 0 = 8; so 208008 is divisible by 8. To test if a number is divisible by 9, add up the digits of the number; if this sum is divisible by 9, then so is the original number. By repeating the test of the sum until a single digit remains, only if this single digit is 9 is the original number divisible by 9, otherwise it gives the remainder when the original number is divided by 9. (This single digit is also called the "digital root" of the number.) For 202008: 2 + 0 + 2 + 0 + 0 + 8 = 12; 1 + 2 = 3; so 202008 is not divisible by 9; it has a remainder of 3 when divided by 9.
Every number is divisible by any non-zero number. Furthermore, 4770 is evenly divisible by both 3 and 9.
8, yes. 9, no.
It's divisible by both (240 times for 9, 270 times for 8)
A number that is divisible by both 8 and 9 must be a multiple of the least common multiple of 8 and 9, which is 72. Therefore, any number that is a multiple of 72 will be divisible by both 8 and 9. Examples of such numbers include 72, 144, 216, and so on.
30,030,003 is divisible by 9 without a remainder. Both 30,030,003 and 9 are odd numbers. Therefore, an even number such as 8 would always leave a remainder.
72
18324 is divisible by both 4 and 9. 18324 / 4 = 4581 18324 / 9 = 2036 You can simply check if a number is divisible by 4 if the last two digits are divisible by 4. The last two digits are 24. 24 is divisible by 4. (24/4=6) An easy way to check if a number is divisible by 9 is if sum of the digits are divisible by 9. 18324 1+8+3+2+4 =18 18 1+8 =9 9 is divisible by 9, so 18324 is divisible by 9.
If it is divisible by a whole number that isn't 1 and gets another whole number, it is not prime. 8 is divisible by both 2 and 4. 9 is divisible by 3.
is 18 divisible by 9
Yes, 72 is divisible by 9. It is not divisible by 8 or 6.
9 is divisible by both 3 and 9
8/9 They are both divisible by 2
42 is divisible by 14, but not divisible by 8, 5 nor 9.