0, 2, 4, 6 and 8
No, 8 is a multiple of 2.
You need to provide two or more positive integer numbers.
No. 8 is not a multiple of 6.
The least common multiple of 1 and 8 is 8 .
So the first multiple is 1 x 8 = 8. The fifth multiple is 5 x 8 = 40.
40
Quotient = 95 Reminder = 0 760 is a multiple of 8.
It is: 24 - 24 = 0
4- last two digits are a multiple of 4 7-take the last digit and subtract it from the rest of the number and if multiple of 7 (including 0) 8- last three digits are multiple of 8
0 or 2 or 4 or 6 or 8 .
Multiples of 2 are even numbers. Even numbers end in 0, 2, 4, 6 and 8.
0 is a multiple of any number, since n*0 = 0 so 6*0 = 0 and 0 IS a multiple.
8+4+0=12 1+2=3 Yes it is.
That is 8001. For a number is divisible by 9, the digits must sum up to 9 (or a multiple of 9). So for 8000, the digits sum to 8 [8 + 0 + 0 + 0 = 8]. So you're only 1 away from 9 [8 + 0 + 0 + 1 = 9]
0, 2, 4, 6 and 8
No, 8 is a multiple of 2.