no
not by 10 as 216 ends in 6 not 0
same with 5 as does not end in 5 or 0
216 = 2 x 108 = 3 x 72 = 4 x 54 = 6 x 36 = 9 x 24
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Last digit of 216 is even (one of {0, 2, 4, 6, 8}) so 216 is divisible by 2
6 + 1 + 2 = 9 which is divisible by 3 so 216 is divisible by 3
Last 2 digits are 16 which are divisible by 4, so 216 is divisible by 4
Last digit is not 0 nor 5, so 216 is NOT divisible by 5
216 is divisible by both 2 and 3 so 216 is divisible by 6
6 + 1 + 2 = 9, so 216 is divisible by 9
Last digit is not 0, so 216 is NOT divisible by 10
216 is divisible by 2, 3, 4, 6, 9.
216 is NOT divisible by 5 nor 10.
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by 2 is 171 by 3 is 114 by 4 is not evenly divisible nor by 5, by 6 it is evely divisible 57 times, by 9 its 38 not evenly by 10.
70 can't be divisible by three because the sum of its digits isn't divisible by three. Ditto for nine. 70 is divisible by 2, 5 and 10.
They are: 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90.
The factors of 90 are: 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90 The factors of 108 are: 1, 2, 3, 4, 6, 9, 12, 18, 27, 36, 54, 108
It is divisible by 2, 5 and 10 but not the rest.
90 and any number multiplied by 90. 90,180,270,360,450,540 and so on
Any element of the set of numbers of the form *k, where k is an integer, is evenly divisible. However, 308 is not evenly divisible by either.