no
not by 10 as 216 ends in 6 not 0
same with 5 as does not end in 5 or 0
216 = 2 x 108 = 3 x 72 = 4 x 54 = 6 x 36 = 9 x 24
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Last digit of 216 is even (one of {0, 2, 4, 6, 8}) so 216 is divisible by 2
6 + 1 + 2 = 9 which is divisible by 3 so 216 is divisible by 3
Last 2 digits are 16 which are divisible by 4, so 216 is divisible by 4
Last digit is not 0 nor 5, so 216 is NOT divisible by 5
216 is divisible by both 2 and 3 so 216 is divisible by 6
6 + 1 + 2 = 9, so 216 is divisible by 9
Last digit is not 0, so 216 is NOT divisible by 10
216 is divisible by 2, 3, 4, 6, 9.
216 is NOT divisible by 5 nor 10.
They are: 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90.
The factors of 90 are: 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90 The factors of 108 are: 1, 2, 3, 4, 6, 9, 12, 18, 27, 36, 54, 108
It is divisible by 2, 5 and 10 but not the rest.
90 and any number multiplied by 90. 90,180,270,360,450,540 and so on
Any element of the set of numbers of the form *k, where k is an integer, is evenly divisible. However, 308 is not evenly divisible by either.
90 is divisible by: 1 2 3 5 6 9 10 15 18 30 45 90.
The number 90 is divisible by both 2 and 3.
90
as 9 is made of 3 times 3 so any number (such as 90) which is divisible by 9 will also be divisible by 3 and the answer will be 3 times bigger so 90/9 is 10 then 90/3 = 30 which is 10 x 3 Example: same for any number that is divisible by 14 will also be divisible by 7 (or also 2) as 14 = 7 x 2 or divisible by say 50 is also divisible by 5 or 10 as 50 = 5 x 10 and so on ...
90
90.
Any multiple of 90.
Oh, dude, you're asking me to find a number that's divisible by 2, 3, 5, and 9? That's like asking me to find a unicorn at a dog show! The smallest number divisible by all those numbers is their least common multiple, which is 90. So, yeah, 90 is your lucky winner.
1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90
90 is divisible by 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90.
90
90 is the correct answer