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This depends on how you define your domain and codomain. f(n)=n/3 is one to one and onto when f is from R to R, but if we define f: X --> Y, where X = [0,3] and Y = [0,3], then f maps [0,3] to [0,1], so f is not onto in this case.

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Q: Is the function n divided by 3 one to one and onto?
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Y equals 4x plus 3 is this a one to one function or an onto function and does it have an inverse function?

Assuming the domain and range are both the real numbers (or rationals): Yes, it is 1 to 1 Yes, it is onto and the inverse is x = (y-3)/4


In the inverse variation function what happens to the output when the function's input is multiplied by 3?

the output is divided by 3.


Is every on-to function a one-one function?

No. The function y = x2, where the domain is the real numbers and the codomain is the non-negative reals is onto, but it is not one to one. With the exception of x = 0, it is 2-to-1. Fact, they are completely independent of one another. A function from set X to set Y is onto (or surjective) if everything in Y can be obtained by applying the function by an element of X A function from set X to set Y is one-one (or injective) if no two elements of X are taken to the same element of Y when applied by the function. Notes: 1. A function that is both onto and one-one (injective and surjective) is called bijective. 2. An injective function can be made bijective by changing the set Y to be the image of X under the function. Using this process, any function can be made to be surjective. 3. If the inverse of a surjective function is also a function, then it is bijective.


In the inverse variation function what happens to the output when the function input value is divided by 3?

The output is multiplied by 3.


What is difference between one to one function and onto function?

In simple words, a one-to-one function is a function such that for every input there is a unique output. An onto function is such that ALL the elements in the out are used, something which is not necessary for a one-to-one function. Draw a set A, which contains 3 elements, a, b, c and d. Draw another set B, containing elements e, f, g and h. Make an arrow from "a" to "d", "b" to "d", then "c" to "e" and "d" to "f". Draw the two sets A and B again. This time make an arrow from "a" to "d", "b" to "d", then "c" to "e" and "d" to "e". The fact that "f" in set B has not been used, DOES NOT makes this function an onto function.


In the inverse variation function what happens to the output when the function's input value is divided by 3?

The output is tripled.


What is one and one and one ninth divided by one third?

It is: (1 and 1/9) divided by 1/3 = 3 and 1/3


What is 3n divided by 1?

3


What is one third divided by one 9th?

It is: 1/3 divided by 1/9 = 3/1 => 3


WHAT IS 2 AND ONE FOURTH DIVIDED BY 3?

2 and one fourth divided by 3 = 0.6666666666666666


In the inverse variation function what happens to the output when the functions input is multiplied by 3?

the output is divided by 3.


What happens to the output when the function's input value is divided by 3 In the inverse variation function?

The output is three times as large.