This depends on how you define your domain and codomain. f(n)=n/3 is one to one and onto when f is from R to R, but if we define f: X --> Y, where X = [0,3] and Y = [0,3], then f maps [0,3] to [0,1], so f is not onto in this case.
1
All even numbers can be divided by 2. 6/100 = 3/50
Anything divided by one is the original number.
1 and 3/4 = 1.751 divided by 3 divided by 4 = 0.083333 repeating1 divided by 3/4 = 1.3333 repeating
1/6 is one fraction. You need at least two fractions to find something in common.
Assuming the domain and range are both the real numbers (or rationals): Yes, it is 1 to 1 Yes, it is onto and the inverse is x = (y-3)/4
the output is divided by 3.
No. The function y = x2, where the domain is the real numbers and the codomain is the non-negative reals is onto, but it is not one to one. With the exception of x = 0, it is 2-to-1. Fact, they are completely independent of one another. A function from set X to set Y is onto (or surjective) if everything in Y can be obtained by applying the function by an element of X A function from set X to set Y is one-one (or injective) if no two elements of X are taken to the same element of Y when applied by the function. Notes: 1. A function that is both onto and one-one (injective and surjective) is called bijective. 2. An injective function can be made bijective by changing the set Y to be the image of X under the function. Using this process, any function can be made to be surjective. 3. If the inverse of a surjective function is also a function, then it is bijective.
The output is multiplied by 3.
In simple words, a one-to-one function is a function such that for every input there is a unique output. An onto function is such that ALL the elements in the out are used, something which is not necessary for a one-to-one function. Draw a set A, which contains 3 elements, a, b, c and d. Draw another set B, containing elements e, f, g and h. Make an arrow from "a" to "d", "b" to "d", then "c" to "e" and "d" to "f". Draw the two sets A and B again. This time make an arrow from "a" to "d", "b" to "d", then "c" to "e" and "d" to "e". The fact that "f" in set B has not been used, DOES NOT makes this function an onto function.
The output is tripled.
the output is divided by 3.
The output is three times as large.
It is: (1 and 1/9) divided by 1/3 = 3 and 1/3
3
It is: 1/3 divided by 1/9 = 3/1 => 3
2 and one fourth divided by 3 = 0.6666666666666666