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The actual dimensions of the TV (vs. the screen) will depend upon the width of the frame surrounding the screen. Some variable include the location of the speakers as some units have the speakers on the side of the panel and others have the speakers below the screen.
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Length of a rectange is 5m greater than the width the perimeter is 84m2 what is the length and width?
Rectangular perimeter = 2(Length + Width) Width = a Length = a+5 Then, 84 = 2(a+a+5) 42 = 2a+5 (42-5)/2 = a = 18.5m = Width Length = a+5 = 23.5m
What is the perimeter of a rectangle with length 42 inches?
A rectangle has two dimensions, length and width. You haven't said what the width is. The perimeter is the distance around the rectangle. Imagine going round it. You would go 42 inches, then a width, then another 42 inches, then another width. In general, the perimeter of a rectangle is twice its length plus twice its width.
The length of a rectangle is 5 cm what is its width?
42
What is the length and width of India gate?
Height 42 mtrs
What is the perimeter of 42 yards?
None. 42 yards is a length with no width. Therefore it cannot have a perimeter.
A rectangle has a width equal to 8 feet and length equal to 14 feet a similar rectangle has a length equal to 42 feet what is its width?
The width is 24 feet.
How do you find the area of a rectangle with a length of 7 and a width of 6?
Multiply the length by the width: 7 x 6 = 42. If the the units of length and width are metres (m) then the are would be metres squared (m2).
What is the width of a rectangle if length is 7 and perimeter is 42?
Let w be the width, then 2(7 + w) = 42 or 14 + 2w = 42 or 2w = 42 - 14 or 2w = 28 w = 14
If the length of a rectangle is twice the width the perimeter is 42 inches what is the width?
2 (x + 2x) = 42 x + 2x = 21 3x = 21 Therefore, x = 7 The width of the rectangle is 7 inches. The length of the rectangle is 14 inches.
Rectangle ABCD has a perimeter of 112 inches If the width is 14 inches what is the length?
Perimeter = width*2 + length *2 112 = 14 * 2 + length * 2 56 = 14 + length length = 56 - 14= 42
The length of a rectangle is 3 ft more than twice its width and the perimeter of the playing field is 258 ft Find the dimensions of the playing field?
Let the length be 2x+3 and the width be x: So: 2*(2x+3+x) = 258 => x = 42 feet Therefore: length = 87 feet and width = 42 feet Check: 2*(87+42) = 256 feet
What is the width of the rectangle with an area of 42 square feet The length is two feet longer than the width?
The width is 5.557 feet to 3 decimal places and its length is 7.557 feet to 3 decimal places
