1, 2, 4, 8, 16, 32 1, 2, 4, 8, 16, 32, 64
44
1, 2, 4, 8, 16, 32, 64 All but 1 and 2 are composite.
1, 2, 4, 8, 16, 32, 64 -1, -2, -4, -8, -16, -32, -64
Common factors of 64 and 16 are: 1, 2, 4, 8, and 16.
This sequence is called the doubling sequence.
1 - 2 - 4 - 8 - 16 - 32 - 64 the sequence doubles
-64
512 / 2 = 256 256 / 2 = 128 128 / 2 = 64 64 / 2 = 32 32 / 2 = 16 16 / 2 = 8 8 / 2 = 4 4 / 2 = 2 2 / 2 = 1
No.
-2
24. It should be 32 which is double of 16
The given sequence is the sequence of perfect squares starting from 1. The nth term of this sequence can be represented as n^2. Therefore, the 8th term would be 8^2, which equals 64. So, the 8th term of the sequence 1, 4, 9, 16, 25 is 64.
4 16 36 I'd say 64 100 144 Why ? 4 16 36... if you take the square root you get 2 4 6 so you can reason the sequence is 2 4 6 8 10 12 14... If you square that again you get 4 16 36 64 100 144 196 :-)
They are square numbers
You are multiplying each number in the sequence by -2. Therefore, the next number in the sequence after 32 is -64.
1, 2, 4, 8, 16, 32 1, 2, 4, 8, 16, 32, 64