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Q: The electric similarity between NH3 and H3O?
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How do you reach Green Valley in Murbad from Thane?

Take a right nh3 highway after you reach Murbad City I have taken a part of land in Green Valley.It is faboulous and the contact person is Sagun Bhadkamkar.Ph no-9767743143 visit the website-http://greenvallygreendream.blogspot.com/ -or- http://green-dream.in/ hope i helped.


How to go from Pune to Indore by Road?

{| ! colspan="2" | Driving Directions | ---- 1 Straight(0.2 km) on Veer Samtaji Ghorpade Rd going toward Dr Babasaheb Ambedkar Rd ---- 2 1st Left onto Dr Babasaheb Ambedkar Rd(NH9 Hwy), go 0.5 km.Via Juna Bazar Jabal. Enter Shivaji Nagar. ---- 3 Continue down NH9 Hwy: 0.5 km ---- 4 1st Right (past Maharashtra Industrial Development Mandal on the left) onto Mumbai Pune Rd(NH4 Hwy), go 0.2 km ---- 5 1st Left (past National Bank For Agricultural and Rural Development on the left) onto Mumbai Pune Rd(NH4 Hwy), go 5.3 km.Via Sagar Society, Ashok Nagar, Range Hills. Enter Bopadi. ---- 6 Straight on Mumbai Pune Rd(NH4 Hwy) flyover, go 4.2 km.Via Changla Crescent Area.Enter Pimpri Chinchwad. Via Konal Puram, Sewa Nagar, Kasarwadi. Enter Defence Area. ---- 7 Right onto NH50 Hwy, go 128 km.Via Ram Nagar, Santi Nagar Basti, Gavli Vasti, Shiv Ganesh Nagar, Indrani Nagar, Bhusari, Kendriya Vihar, Bohadey Basti, Nageshwar Nagar Moshi, Anna Bhai Matey Nagar.Enter Pune District at 13 km.Via Chakan, Rajgurunagar (Khed), Manchar at 33 km.Enter Ahmadnagar District at 88 km.Enter Sangamner at 127 km. ---- 8 Right onto SH10 Hwy, go 6 km.Leave Sangamner. ---- 9 Take Slight Left, go 40 km ---- 10 Left onto SH2 Hwy, go 20 km.Via Kopargaon at 3.2 km.Enter Nashik District at 9.6 km.Enter Yevla at 19 km. ---- 11 Continue down SH14 Hwy: 51 km.Leave Yevla at 1 km.Via Manmad at 25 km. ---- 12 Continue down SH16 Hwy: 5.6 km ---- 13 Continue down NH3 Hwy: 3 km ---- 14 Rightonto NH3 Hwy, go 4.7 km.Via Malegaon at 1.8 km. ---- 15 Left onto NH3 Hwy, go 42 km.Enter Dhule District at 15 km. ---- 16 Left onto NH3 Hwy, go 247 km.Via Dhule at 4.4 km.Enter Madhya Pradesh at 85 km.Via Sendhwa at 104 km.Via West Nimar District at 165 km.Enter Dhar District at 171 km.Via Dhamnod at 178 km.Enter Indore District at 196 km.Via Manpur, Mhowgaon, Rau at 228 km.Enter Indore at 246 km. ---- 17 Continue down Agra Bombay Rd(NH3 Hwy): 4.6 km (Past Rajendra Nagar Police Station on the left) ---- 18 Left (past Bhanwara Kua Police Station on the right) onto SH27 Hwy, go 1.9 km ---- 19 Right(past Bank Of Maharashtra on the left) onto SH27 Hwy, go 0.4 km ---- 20 Left onto Navalakha Rd(NH59 Hwy), go 0.1 km ---- 21 Take 2nd Right (past Mandir on the left), go 0.5 km ---- 22 2nd Right (past State Bank Of Saurashtra on the right) onto Jawahar Marg, go 0.2 km ---- 23 Take 3rd Left, go 0.1 km ---- 24 Take 2nd Right (past Verma Nursing Home on the right), go 0.1 km ---- 25 Take Slight 2nd Left, go 0.2 km ---- 26 4th Right (past Shri Krishna Cinema on the left) onto M.G. Rd, go 0.1 km ---- 27 Take Slight 1st Left (past Commissioner Office (Police Station) on the left), go 0.2 km ---- 28 Arrive at destination |}


How many moles of strontium hydroxide are in 4.25 g of strontium hydroxide?

You must first find the molar mass of the element or compound. Use the periodic table (see the link to the left of the answer). If the chemical is an element, just read off the atomic mass from the periodic table. If it is a compound, you must know the molecular formula, and then you find the total molar mass of the compound by adding up the atomic masses of each atom in the compound. The unit of the molar mass will be in grams per moles (g/mole)Once you have the molar mass, you can easily convert from grams to moles, and also from moles to grams.Number of moles = (# of grams) ÷ (molar mass)Number of grams = (# of moles) × (molar mass)Here are a two examples:Example 1:How many moles are in 5 grams of O2?The molar mass of O2 = 16.00 g/mole x 2 (for 2 atoms of oxygen) or 32.00 g/mole.5 g of O2 ÷ (32 g/mole) = 0.15625 molesExample 2:How many grams does 4 moles of NH3 weigh?The molar mass of NH3 = 14.01 + (3 × 1.01) = 17.04 g/mole4 moles × 17.04 g/mole = 68.16 gramsGrams in a MoleIn chemistry, a mole is considered to be Avogadro's number (6.02 × 1023) of molecules (or anything) of a substance - so depending on the density of the substance, the mass of that amount of the substance could vary widely. One mole of hydrogen, for example, would have a different mass than one mole of lead. The question compares two different measurements of a given substance, rather like asking "how heavy is a gallon?". The question becomes "A gallon of what"?