The product of the prime factors of 235 is 235. The product of the (not necessarily distinct) prime factors of any number is that number.
As a product of its prime factors: 2*2*5*5*17 = 1700
5 x 5 x 5
Prime factorization of 187 is: 11 x 17 Answer: 11 & 17
two factors is a binomial three factors is a trinomial four of more is a polynomial the product of any of these is just a polynomial
3 x 5 x 5 = 75
5 x 5 x 5 x 5 = 625
5 x 5 x 5 = 125
5 x 5 x 277 = 6,925
250 = 2 x 5 x 5 x 5
No. If the number by which you multiply 5 is even, the product will always end in "0" and will be even:5 x 2 = 105 x 8 = 405 x 18 = 90If the number by which you multiply 5 is odd, the product will always end in "5" and will be odd:5 x 3 = 155 x 9 = 455 x 31 = 155
3*(x-5)=39 x-5=13 x=18
3 x 3 x 5 x 5 x 7
The product of the prime factors of 150 is 150 (2 x 3 x 5 x 5 = 150).
n x (n -5)
x 35
5 x 4 = 20