The prime factorization of 1955 is 5 x 17 x 23. To find three prime numbers whose product is 1955, we need to find a combination of these prime factors that multiply to 1955. The prime numbers less than 30 that can be formed from these factors are 5, 17, and 23. Therefore, the three prime numbers less than 30 whose product is 1955 are 5, 17, and 23.
Well, well, well, look at you trying to stump me. The prime numbers less than 30 that multiply to 1955 are 5, 13, and 31. Yep, you heard me right, 31 is not less than 30, but it sure is a Prime number that gets the job done.
Oh, what a happy little math problem we have here! Let's see, if we think about prime numbers less than 30, we can find that 5, 13, and 31 are our three prime numbers. When we multiply them together, we get 1955. Isn't that just a delightful little math puzzle to solve? Happy calculating, my friend!
It means write down three pairs of numbers that are relatively prime like 4 and 9, 5 and 6, 13 and 25
A set of numbers whose GCF is one are called co-prime or relatively prime
There are two numbers, 7 and 49, whose smallest prime factor is 7 in the set of numbers from 1 to 100.
Any pair of prime or relatively prime numbers.
30 and 90 are two of many numbers whose prime factors include 2, 3, and 5.
Three and Seven
two prime numbers whose product is 141 = 3 & 47
3 and 7 are prime numbers whose product is 21.
They are: 3*5*7 = 105
17 and 3 are two prime numbers whose sum is 20. Their product is 51.
5 x 17 x 23
The product of the prime numbers 19 and 23 is 437.
5 * 17 * 23 =1955
There are no such numbers.
There are no two numbers whose product is 23 and whose sum is 10. 23 is a prime number, and the only numbers whose product is 23 are 23 and 1. A prime number can only be divided by itself and 1.
3, 5, and 7 are three prime numbers whose average is 5.
The prime factorization of 15 is 3 x 5 because three and five are the only prime numbers whose product is 15.