i need fourteen points of Quaid e Azam in urdu language.
The roots (or solutions) are the numbers that 'w' must be in order to make the equation true.Since the highest power of 'w' in the equation is the first power, there's only one solution.3w - 14 - 6 = 21Combine the -14 and the -6 on the left side:3w - 20 = 21Add 20 to each side:3w = 41Divide each side by 3 :w = 41/3 = 132/3
Langley Speedway TV - 2010 Points 1-7 was released on: USA: 14 August 2010
Drive - 2007 The Starting Line 1-1 is rated/received certificates of: USA:TV-14
Fault Line - 2009 I was released on: USA: 14 July 2009 (NewFilmmakers Los Angeles) USA: 14 July 2009 (Los Angeles, California) USA: 8 August 2009 (International Film Series)
Points: (14, 6) (21, 9) (7, 3) Slope of the line: 3/7 Equation of the line: 7y = 3x and it has no y intercept
Points: (7, 3) (14, 6) (21, 9) Slope: 3/7 Equation: 7y=3x
The slope works out as: 3/7 The equation works out as: 7y = 3x
The slope of the line is (6-3)/(14-7) = 3/7 The equation is: y - 3 = (3/7)(x - 7) → y - 3 = (3/7)x - 3 ← y = (3/7)x
vertical
If you mean points of (-10, -6) and (-1, 8) then the slope of the line is 14/9 which is in a positive direction
It is in its general form: 2x+7y-14 = 0
(-2, 11)(-3, 14)(2, -1)
Points: (-2.5, -0.5) and (4.5, -1) Slope: -1/14 Equation: y = -1/14x-19/28 in slope intercept form
Points: (-2.5, -0.5) and (4.5, -1) Slope: -1/14 Equation: 14y = -x-9.5 or x+14y+9.5 in its general form
(0, -14) and (14, 0) are both points on the line of y = -14 + x. Any point where the first number (also known as the x-coordinate) is 14 more than the second number (the y-coordinate) is on that line.
It works out as: 11y = -5x+519 or as 5x+11y-519 = 0