distinct prime factor of any number can be done in this way
like I.E ;;;;;
FORTY TWO
FORTY TWO /TWO=TWENTY ONE/3=7
SO TWO ,THREE,AND 7
ARE DISTINCT PRIMEFACTORS
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Prime factors of 42 are: 2, 3 and 7 Prime factors of 237 are: 3 and 79
42 - The prime factors are: 2, 3 and 7660 - The prime factors are: 2, 3, 5 and 11
The factors of 12 are: 1, 2, 3, 4, 6, and 12.The prime factors of 12 are: 2 and 3.The factors of 42 are: 1, 2, 3, 6, 7, 14, 21, and 42.The prime factors of 42 are: 2, 3, and 7.
To find the common factors of 42 and 231, we first need to find the prime factorization of each number. The prime factorization of 42 is 2 x 3 x 7, and the prime factorization of 231 is 3 x 7 x 11. The common factors of 42 and 231 are the prime numbers that appear in both factorizations, which are 3 and 7. Therefore, the two common factors of 42 and 231 are 3 and 7.
The prime factors of 42 are 2, 3 and 7.