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Just multiply 9 with different integers:

9 x 0

9 x 1

9 x 2

etc.

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Wiki User

10y ago

What else can I help you with?

Related Questions

How do the digits in each product relate to the factor 9?

If they are multiples of 9, the digits add up to a multiple of 9.


Why do no digits of a prime number add up to 9?

Because they're in multiples of three - a quick way to tell if a number is a multiple of three is to add up the digits and see if the digits add up to a multiple of three e.g 576, 5+7+6=18, 1+8=9, 9 is a multiple of three


What is noticeable about the sum in the multiples of 9?

That the sum of its digits add up to 9 as for example 9*9 = 81 and 8+1 = 9


What is a number that is between 30 and 56 that is a multiple of 5 and the sum of its digits is 9?

the only multiples of 5 are 30.35.40.45.50, and 55 the only sum to 9 is 45


What multiple of 9 is greater than 110 but less than 120?

117. All multiples of 9 have digits that add up to something divisible by 9. Examples, 117, 36, 45, 54 all have digits that add up to 9.


How you know which numbers are multiples of 3?

If you add up the two digits and they make either 3, 6, or 9


What is a number pattern in multiples of 9?

The sum of the digits is also a multiple of 9. And, if the sum of the digits is too large, you can sum those digits and keep going.


Is 498 a multiples for 9?

The digits of 498 do not add to a multiple of 9 so it isn't.


How can use use the digits 6 and 4 to decide if 64 is the product of 9 and 7?

So there is a rule about multiples of 9 in general: something is a multiple of 9 if and only if its digits add up to a multiple of 9. 6+4 = 10, so it is not a multiple of 9. There's also a neat trick to remembering the multiples of 9 below 99 with your fingers, but you can look this up if you're interested.


What is the rule for multiples of 9?

The total sum of the digits has to equal nine.


How many 3 digit counting numbers are not multiples of 5?

There are 720 of them. The three digit counting numbers are 100-999. All multiples of 5 have their last digit as 0 or 5. There are 9 possible numbers {1-9} for the first digit, There are 10 possible numbers {0-9} for each of the first digits, There are 8 possible numbers {1-4, 6-9} for each of the first two digits, Making 9 x 10 x 8 = 720 possible 3 digit counting numbers not multiples of 5.


What is the smallest multiple of 45 that only has 1 and 0 as digits?

You can experiment a bit for this one. Or you can apply some reasoning:* Multiples of 45 end with 5 or 0. To avoid a 5, you would have to multiply by an even number; that is, you are looking for multiples of 90. * Since multiples of 90 are also multiples of 9, the sum of the digits must needs be 9. This means that you must provide 9 ones (or a multiple thereof), and the last digit must be 0. The smallest number that satisfies these criteria is 1111111110.