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(1,35)(5,7)

(56,1)(28,2)(14,4)(8,7)

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βˆ™ 12y ago
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βˆ™ 8y ago

56 = 1 x 56, 2 x 28, 4 x 14, 7 x 8, 8 x 7, 14 x 4, 28 x 2, 56 x 1

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βˆ™ 12y ago

(56,1)(28,2)(14,4)(7,8)

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βˆ™ 12y ago

(56,1)(28,2)(14,4)(8,7)

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βˆ™ 8y ago

7,8

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Q: What are the factor pairs of 56 and 35?
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