If a polynomial has factors x-6 and x-3 it will equal 0 if either factor equals 0 since the other factor then would be multiplied by 0. ie. 0 * (x-6)=0 and 0 * (x-3)=0. so x=3 or 6
Two factors. 9 and 4 are factors of 36.
4 and 3 are factors of 12.
The factors of 24 are 1,2,3,4,6,8,12 and 24. For them to be common, they need to be compared to another set of factors.
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yes there are because anything times 0 equals 0. so there are millions of numbers that you multiply to equal zero. one factor of 0 is 2 or maybe 3 or 4 or 5 because 0 times 5 equals o, 564,453,895,373 times 0 equals
0. Any number multiplied by zero equals zero.
equation works for n = 0 and n = 1 as factors are n and n - 1
First, factorise: x2 + 5x - 6 = (x + 6)(x - 1) = 0; whence, either x + 6 = 0, or x - 1 = 0. The product of two factors equals zero, exactly when one or other of the two factors equals zero. Thus, the solution must be x = 1 or -6. If x equals either of those two values, then the original equation will be true.
Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.
That factors to (x - 2)(x + 7)
15 percent 0 equals 0; 0 percent 15 equals 0. Both the above are true
x2 = -11x - 10 x2 + 11x + 10 = 0 (x + 1)(x + 10) = 0
yes
k = -3; factors are (9x + 3)(x - 1)
y=3, and y=-3. 6y² - 54 = 0 factors to 6(y² - 9) = 0 --> 6(y + 3)(y - 3) = 0
0 has no factors.