121y2 - 4 = (11y - 2)(11y + 2)
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If a polynomial has factors x-6 and x-3 it will equal 0 if either factor equals 0 since the other factor then would be multiplied by 0. ie. 0 * (x-6)=0 and 0 * (x-3)=0. so x=3 or 6
4 and 3 are factors of 12.
Two factors. 9 and 4 are factors of 36.
The factors of 24 are 1,2,3,4,6,8,12 and 24. For them to be common, they need to be compared to another set of factors.
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