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42 = 1 x 42, 2 x 21, 3 x 14, 6 x 7, 7 x 6, 14 x 3, 21 x 2, 42 x 1

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What are the pairs of 42?

The pairs of 42 are the sets of two numbers that multiply together to equal 42. These pairs include (1, 42), (2, 21), (3, 14), (6, 7), and their negatives: (-1, -42), (-2, -21), (-3, -14), and (-6, -7). Each pair provides a different combination of factors that result in the product of 42.


What are the foctors of 42?

The factors of 42 are the numbers that can be multiplied together to yield 42. They include: 1, 2, 3, 6, 7, 14, 21, and 42. In pairs, the factors can be represented as (1, 42), (2, 21), (3, 14), and (6, 7). Thus, 42 has a total of eight factors.


Highest common factors of these two pairs 24 and 42?

The Greatest Common Factor (GCF) is: 6


How do you make a factor firework for 42?

To make a factor firework for 42, you need to find all the factors of 42 by listing all the pairs of numbers that multiply together to give 42. The factors of 42 are 1, 2, 3, 6, 7, 14, 21, and 42. You can then arrange these factors in a fun and visually appealing way to represent a factor firework display.


How do you connect all the factor pair of 21 and 42?

(21,1)(7,3) (42,1)(21,2)(14,3)(7,6) Since 21 is a factor of 42, all the factors of 21 will be included in the factor pairs of 42.


What are the factors of 84 in pairs?

1, 2 3, 4 6, 7 12, 14 21, 28 42, 84


What multiplies to get 42 but adds up to get 8?

There are no two numbers that multiply to 42 and add up to 8. The pairs of factors of 42, such as (1, 42), (2, 21), (3, 14), and (6, 7), do not sum to 8. Therefore, it is not possible to find such numbers.


What are all the factor pairs of 42?

Factor pairs of 42 are 1 x 42, 2 x 21, 3 x 14, and 6 x 7.


What are the factor pairs for 42?

42,121,214,37,6


The factors of 42?

the factors of 42 are 1,42,6,7,2,21,3,14


What multiplies to 1764 and adds to 84?

1848


If pairs of factors separate independently of other pair factors you are dealing with?

If pairs of factors separate independently of other pairs of factors, you are dealing with the: Law of independent assortment