t4-81 is a difference of 2 squares and can be written as (t2-9)(t2+9)
t2+9 can't be further factorised but t2-9 is a difference of 2 squares again and can be factorised to (t+3)(t-3)
so the factors of t4-81 are :(t2+9)(t+3)(t-3)
Hope this helps :-)
I believe the answer you are looking for is (t - 3)(t + 3)(t 2 + 9)
1, 29
1, 31
They are: 2 and 11
1, 2, 11 and 22
1, 7, 13, 91.
1, 3, 11, 33.
1, 3, 7, and 21 are.
2, 5, 10, 25
1, 2, 4, 8, 16.
Its prime factors are 2 and 3
1, 2, 4, 31, 62, 124.
1, 2, 4, 5, 10, and 20