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t4-81 is a difference of 2 squares and can be written as (t2-9)(t2+9)

t2+9 can't be further factorised but t2-9 is a difference of 2 squares again and can be factorised to (t+3)(t-3)

so the factors of t4-81 are :(t2+9)(t+3)(t-3)

Hope this helps :-)

I believe the answer you are looking for is (t - 3)(t + 3)(t 2 + 9)

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15y ago

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More answers

1, 3, 9, 27, 81.

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8y ago
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Q: What are the factorsof 81?
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