The multiples of 6 must total 270 ÷ 6 = 45
Let the smallest of the 5 consecutive numbers be n
Then n + (n + 1) + (n + 2) + (n + 3) + (n + 4) = 45
5n + 10 = 45 : 5n = 45 - 10 = 35
n = 35/5 = 7
The numbers are 7,8,9,10, 11
The multiples of 6 are thus 42, 48, 54, 60 & 66 and their total = 270.
Chat with our AI personalities
Multiples are numbers that are evenly divisible by the original number (270). So, 540, 810, and so on.
7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91, 98 and just keep adding 7 until you get to 266.
The LCM of 9 and 10 is 90. Other multiples include 180, 270 and 360.
LCM = 9x5x2 = 90 all multiples are 90, 180, 270, etc
90, 180, 270
The first 5 common multiples are the first 5 multiples of their lowest common multiple (LCM) LCM(9, 10) = 90 → first 5 common multiples are 90, 180, 270, 360, 450.
these are some of the multiples: 30, 60, 90, 120, 150, 180, 210, 240, 270, 300, etc. you can go on they're infinite hope i helped :)