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The multiples of 6 must total 270 ÷ 6 = 45

Let the smallest of the 5 consecutive numbers be n

Then n + (n + 1) + (n + 2) + (n + 3) + (n + 4) = 45

5n + 10 = 45 : 5n = 45 - 10 = 35

n = 35/5 = 7

The numbers are 7,8,9,10, 11

The multiples of 6 are thus 42, 48, 54, 60 & 66 and their total = 270.

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14y ago

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