The infinite set of numbers of the form n*sqrt(2) where n is any integer.
However, since sqrt(2) is one of the factors, there is no obvious reason to restrict the other factor to an integer. In that case, the answer is, at least the infinitely many numbers of the form x*sqrt(2) where x is any real number. But why restrict to real numbers? Why not include complex multiples?
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It's not. 4 is a multiple of 2. 2 is a factor of 4 because it can divide into 4 evenly with no remainder.
Since 4 is a multiple of 2, all the multiples of 4 will be common.
Multiples of 2 are even numbers. All even numbers end in 0, 2, 4, 6 or 8.
If ordered by size, only every other multiple of 2 is a multiple of 4. All multiples of 4 are multiples of 2.
Yes, for example the multiples of 2 are: 2, 4, 6, 8, 10, 12, 14, ......etc. (all even numbers are multiples of 2) or multiples of 3 are 3, 6, 9, 12, 15, 18, 21, ....... etc.