0
The infinite set of numbers of the form n*sqrt(2) where n is any integer.
However, since sqrt(2) is one of the factors, there is no obvious reason to restrict the other factor to an integer. In that case, the answer is, at least the infinitely many numbers of the form x*sqrt(2) where x is any real number. But why restrict to real numbers? Why not include complex multiples?
Still curious? Ask our experts.
Chat with our AI personalities
Steve
Taiga
Judy
Add your answer:
Earn +20 pts
Why is a multiple of 2 a multiple of 4?
It's not. 4 is a multiple of 2. 2 is a factor of 4 because it can divide into 4 evenly with no remainder.
How do you find the common multiples of 2 and 4?
Since 4 is a multiple of 2, all the multiples of 4 will be common.
Do all multiples of 2 end in 02468?
Multiples of 2 are even numbers. All even numbers end in 0, 2, 4, 6 or 8.
What are the first four multiples of 2 and 4?
If ordered by size, only every other multiple of 2 is a multiple of 4. All multiples of 4 are multiples of 2.
Does a natural number have unlimited number of multiples?
Yes, for example the multiples of 2 are: 2, 4, 6, 8, 10, 12, 14, ......etc. (all even numbers are multiples of 2) or multiples of 3 are 3, 6, 9, 12, 15, 18, 21, ....... etc.
