No multiples of 24 are factors of 6.1, 2, 3, 4 and 8 are factors of 24 that are not multiples of 6.
A common multiple of 8 and 6 has the form 2 * 2 * 2 * 3 * n = 24n, where n is any whole number. The other factors are necessary to ensure that what you have is indeed a multiple of both 8 (2 * 2 * 2) and 8 (2 * 3). So for the first 3 common multiples you need to replace n with 1, 2 and 3, giving you 24, 48 and 72.
Yes, for example the multiples of 2 are: 2, 4, 6, 8, 10, 12, 14, ......etc. (all even numbers are multiples of 2) or multiples of 3 are 3, 6, 9, 12, 15, 18, 21, ....... etc.
The first three common multiples of 6 and 8 are the first three multiples of the least common multiple of 6 and 8. 6 = 2 x 3 and 8 = 2 x 2 x 2. Therefore, the LCM of 6 and 8 is 2 x 2 x 2 x 3 or 24. The first three multiples of 24 are 24, 48 and 72.
1/8, 2/8, 3/8, 4/8
What are three common multiples of 2 6 8
All multiples of 8 are also multiples of 2, but not all multiples of 2 are multiples of 8.
lcm(2, 7) = 14 → first 3 common multiples are: 14, 28, 42; lcm(2, 8) = 8 → first 3 common multiples are: 8, 16, 24; lcm(7, 8) = 56 → first 3 common multiples are: 56, 112, 168; lcm(2, 7, 8) = 56 → first 3 common multiples are: 56, 112, 168.
3 multiples and they are all 2 2 * 2 * 2 = 8
Assuming you mean that you want the number of multiples of each, then for 1-100: number of multiples of 2 = 50 number of multiples of 3 = 33 number of multiples of 4 = 25 number of multiples of 6 = 16 number of multiples of 8 = 12 number of multiples of 9 = 11 Assuming you mean that you want the numbers that are multiples of 2, 3, 4, 6, 8 or 9, then some numbers may be multiples of more than one (for example 12 is a multiple of 2, 3, 4 and 6) and so a straight addition of the number of multiples of each cannot be done: Consider 2, 4 and 8 Every multiple of 4 or 8 is also a multiple of 2, so all the multiples of 4 and 8 are counted by the multiples of 2. Consider 3 and 9 Every multiple of 9 is also a multiple of 3, so all the multiples of 9 are counted by the multiple of 3 Consider 2, 3 and 6. Every multiple of 6 is an even multiple of 3, so are counted in both the multiples of 2 and 3. So the total number of multiples of 2, 3, 4, 6, 8 or 9 is the number of multiples of 2 plus the number of multiples of 3 minus the number of multiples of 6: For 1 to 100, Number of multiples of 2 = 50 Number of multiples of 3 = 33 Number of multiples of 6 = 16 So number of multiples of 2, 3, 4, 6, 8 or 9 in 1-100 is 50+33-16 = 67. Assuming you mean that they are multiples of all of 2, 3, 4, 6, 8 and 9, then they must be multiples of the lowest common multiple of 2, 3, 4, 6 ,8, 9 2 = 21, 3 = 31, 4 = 22, 6 = 2131, 8 = 23, 9 = 32 LCM = highest power of the primes used = 2332 = 72 Thus all numbers that are multiples of 2, 3, 4, 6, 8 and 9 are multiples of 72, which means between 1 and 100 only 1 number is a multiple of all of them, namely 72
They are the multiples of 3*8 = 24
4 and 8 are multiples of 2. 6 and 9 are multiples of 3. 40 and 50 are multiples of 10.
Yes, multiples of 8 are also multiples of 2 because 8 is a multiple of 2 itself.
No multiples of 24 are factors of 6.1, 2, 3, 4 and 8 are factors of 24 that are not multiples of 6.
multiples of 8 are also multiples of 2 because anything you times by 8 is an even number
2/8 and 3/12 are equivalent multiples of 1/4, along with an infinite number of others.
yes, for 8 is a multiple of 2