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To answer that, you'll need to have a numerical value for the letters.

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βˆ™ 7y ago
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βˆ™ 6y ago

A, 2A, 3A, 4A and so on.

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Q: What are the number A A B C multiples of?
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What appears t be true if A and B are both multiples of a whole number C?

It appears as if A and B are both multiples of a whole number C.


How do you know a fraction is equivalant to another fraction?

Fractions A/B and C/D are equivalent if the cross-multiples are equal. That is, is A*D = B*CFractions A/B and C/D are equivalent if the cross-multiples are equal. That is, is A*D = B*CFractions A/B and C/D are equivalent if the cross-multiples are equal. That is, is A*D = B*CFractions A/B and C/D are equivalent if the cross-multiples are equal. That is, is A*D = B*C


When A B and C are counting numbers and both A and B are multiples of C what can you say about A plus B?

If A and B are multiples of C, then A + B is also a multiple of C: If A is a multiple of C then A = mC for some integer m If B is a multiple of C, then B = nC for some integer n → A + B = mC + nC = (m + n)C = kC where k = m + n and is an integer → A + B is a multiple of C


What is one characteristic of equivalent ratio?

Their cross-multiples are equal. That is, if a/b = c/d then a*d = b*c


How can you find how many multiples of a number A in a certain range without counting them one by one For example there are 7 multiples of 5 from 9 to 41?

Divide the upper limit of the range by A. Throw out the remainder, if any. Let's call what's left B. Divide the lower limit of the range by A. Throw out the remainder, if any. Let's call what's left C. Subtract C from B. The difference is the number of multiples within the range. 41 ÷ 5 = 8.2 --> B = 8 9 ÷ 5 = 1.8 --> C = 1 B - C = 8 - 1 = 7


What B percent of what number is C?

Let the number be X, then B% = B/100 → B% of X = C → B/100 x X = C → X = C ÷ (B/100) = C x 100/B = 100C ÷ B So to find the number, divide C by B percent.


If A B and C are counting numbers and both A and B are multiples of C what can you say about A plus B?

A + B is also a multiple of C. ------------------------------------------- let k, m and n be integers. Then: A = nC as A is a multiple of C B = mC as B is a multiple of C → A + B = nC + mC = (n + m)C = kC where k = n + m kC is a multiple of C. Thus A + B is a multiple of C.


What is A - B - C if the answer is -13?

There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.


How do you find the smallest largest numbers in c language?

for the largest number: #include<stdio.h> void main() { int a,b,c,number,largestnumber; a=99; b=9; c=77; if(a>b) { number=a; } else if(b>c) { number=b; } else { number=c; } largestnumber=number; printf("%d",largestnumber); }


To find biggest of three number?

Let the numbers be A,B and C and assume that A ≠ B ≠ C 1) Subtract B from A. If the result is a positive number then A > B otherwise B > A. 2) Subtract the greater of A and B from C. If the result is a positive number then C is the largest number otherwise the subtrahend (either A or B) is the largest number.


B is a proper subset of C If the cardinal number of C is 8 what is the maximum number of elements in B?

If every element of B is contained in C, then B is a subset of C. If every element of B is contained in C and B is not the same as C, then B is a proper subset of C.The cardinal number of a set is the number of elements in the set.In this case, C has 8 elements, so B has at most 7 elements.


Which numbers would A B and C be if AxBxC equals 1568?

There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.