3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39 . . .
The first six multiples of 9 are 9, 18, 27, 36, 45, 54. The first six multiples of 12 are 12, 24, 36, 48, 60, 72.
The first 3 multiples of 13 are: 13, 26, and 39.
The answer would be 750,000.
66 is the first one
The first six multiples of 3 are 3, 6, 9, 12, 15, and 18. They are the products of 3 and the nonzero integers 1, 2, 3, 4, 5, and 6.
They are the first three multiples of LCM(5, 9), that is, the first three multiples of 45.
That's an infinite list.
5, 10, 15, 20, 25, 30
12, 24, 36, 48, 60, 72
3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39 . . .
The first five nonzero multiples of 6 are 6, 12, 18, 24 and 30.
9x1= 9 9x2= 18 9x3= 27 9x4= 36 9x5= 45 9x6= 54 Is this what you mean?
The first few multiples of nineteen are:1938577695114133152171190209
Take the first number. Add it to itself. Keep adding that number to the total three more times. The first five nonzero multiples of 9 are 9, 18, 27, 36, and 45. Put another way, let each number equal x. The first five nonzero multiples of x are 1x, 2x, 3x, 4x and 5x.
1 and 13
7