As a product of its prime factors: 2*3*3*3 = 54 Or: 47+7 = 54
2 x 3 x 3 x 3 = 54
There are two prime factors of 45, they are 3 and 5. The prime factors of 54 are 2 and 3.
The product of all factors of the two numbers is 2097152.
The factors of 54 are 1, 2, 3, 6, 9, 18, 27 and 54. For them to be common, they need to be compared to another set of factors, but I'll save you the trouble. The least common factor of any two positive integers is 1.
Factors get multiplied together to make the product45 x 54 = 243045 = factor54 = factor2430 = product
54 = 2 x 33
As a product of its prime factors: 2*3*3*3 = 54 Or: 47+7 = 54
As a product of its prime factors: 2*3*3*3 = 54 or as 2*33 = 54 As a product of its prime factors: 2*3*3*5 = 90 or as 2*32*5 = 90
2*3*3*3 = 54
2 x 3 x 3 x 3 = 54
The prime factors of 54 are: 3 * 3 * 3 * 2 * 1
54 = 2 x 3 x 3 x 3
As a product of its prime factors: 2*3*3*3 = 54
As a product of its prime factors in exponents: 24*54 = 10,000
9*6 = 54
54 x 5 = 270 54 + 5 = 59 The two factors in question are therefore 54 and 5.