LCM(120, 56, 78) = 10920.
Factors of 78: 1, 2, 3, 6, 13, 26, 39, 78Factors of 34: 1, 2, 17, 34Factors of 96: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96GCF (78, 34, 96) = 2
The GCF of 48 and 78 is 6
You need at least two numbers to find a GCF.
The GCF of 42, 48, and 78 is 6.
ot tf fs se nt
That equals 199
2, 3 and 73
12-34-56-78-90 in squence bye fours
The average is 56.
OPTIMAL STORAGE ON TAPES We want to store files of lengths (in MB) {12,34,56,73,24,11,34,56,78,91,34,91,45} on three tapes. How should we store them on the three tapes so that the mean retrieval time is minimized? SOLUTION: STORE FILES BY NON-DECREASING LENGTH First sort the files in increasing order of length. For this we can use heap sort, merge sort or quick-sort algorithms. 11 12 24 34 34 34 45 56 56 73 78 91 91 Now distribute the files: First element 11 Tape 11 1 Tape 2 Tape 3 Second element 12 Tape 11 1 Tape 12 2 Tape 3 Third element 24 Tape 11 1 Tape 12 2 Tape 24 3 Fourth element 34 Tape 11 34 1 Tape 12 2 Tape 24 3 Fifth element 34 Tape 11 34 1 Tape 12 34 2 Tape 24 3 Sixth element 34 Tape 11 34 1 Tape 12 34 2 Tape 24 34 3 Seventh element 45 Tape 11 34 45 1 Tape 12 34 2 Tape 24 34 3 Eigth element 56 Tape 11 34 45 1 Tape 12 34 56 2 Tape 24 34 3 Ninth element 56 Tape 11 34 45 1 Tape 12 34 56 2 Tape 24 34 56 3 Tenth element 73 Tape 11 34 45 73 1 Tape 12 34 56 2 Tape 24 34 56 3 Eleventh element 78 Tape 11 34 45 73 1 Tape 12 34 56 78 2 Tape 24 34 56 3 Twelth element 91 Tape 11 34 45 73 1 Tape 12 34 56 78 2 Tape 24 34 56 3 Thirteenth element 91 Tape 11 34 45 73 1 Tape 12 34 56 78 2 Tape 24 34 56 3
2 is the greatest common factor of 56, 78 and 130.
To get an average, add the numbers together and divide by how many numbers there are.... 33 + 34 + 78 + 56 = 201. 201 / 4 = 50.25
19 28 37 46 45 88 12 34 56 78 90
welll u kiss guy when you are 30 34 90 56 78 56 45 34 19 that kiss a guy
2
The greatest common factor of 12 and 78 is 6.