Any element of the set of numbers of the form 42*k, where k is an integer, is evenly divisible.
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3/6 + 1/3 = 3/6 + 2/6 = 5/6 5 6ths is your answer
The LCM of 3, 5, 6, and 9 is 90
thirty 30 = 2 x 15 = 3 x 10 = 5 x 6 = 6 x 5 furthermore, of 2 3 5 6 the 2 and 3 are not needed, as 6 is already 2 x 3 so only 5 and 6 are in question.
7 + 5 = 12 12 x 6 = 72 72 + 3 = 75 3 + [6 x (5 + 7)] = 75 3 + [6 x 12] = 3 + 72 = 75
Factors of 6: 1, 2, 3, 6 Factors of 15: 1, 3, 5, 15