Any element of the set of numbers of the form 42*k, where k is an integer, is evenly divisible.
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∙ 6y agoWiki User
∙ 10y agothey all go into 30(5 times 6=30,3 times 10=30 and 6 times 5=30
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∙ 6y agoAny multiple of 42.
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∙ 6y agoAny multiple of 42.
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∙ 6y agoThe LCM is 63
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∙ 11y ago126
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∙ 7y ago42
3/6 + 1/3 = 3/6 + 2/6 = 5/6 5 6ths is your answer
The LCM of 3, 5, 6, and 9 is 90
thirty 30 = 2 x 15 = 3 x 10 = 5 x 6 = 6 x 5 furthermore, of 2 3 5 6 the 2 and 3 are not needed, as 6 is already 2 x 3 so only 5 and 6 are in question.
7 + 5 = 12 12 x 6 = 72 72 + 3 = 75 3 + [6 x (5 + 7)] = 75 3 + [6 x 12] = 3 + 72 = 75
Factors of 6: 1, 2, 3, 6 Factors of 15: 1, 3, 5, 15
They have a common factor of 3.1, 2, 3, and 6 go into 6.1, 3, 5, and 15 go into 15.1 and 3 both go into 6 and 15.
no need for 3 as it already goes in to 6 so 5 6 7 go in to 210 210 = 5 x 42 = 6 x 35 = 7 x 30
.6
7 and 5 are prime numbers, but 3*2=6
i couldn't understand your question that well but if u meant like "5/3" then the answer is 1.666(6 go on for a while)7. or if it were "3/5" .6
8
3 with remainder 3.
3 with remainder 5
60
It is the LCM which is 210
20 divided by 6 is 3 with remainder 2.
5/3 × 3/6 = 5/6