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The first six multiples of 3 are 3, 6, 9, 12, 15, and 18.

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Q: What does 6 multiples of 3 mean?
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Related questions

What is the mean of the first five multiples of 3?

3, 6, 9, 12, 15 The mean is 9.


What are the multiples of 6 4 3?

Multiples of 6: 1,2,3,6 Multiples of 4: 1,2,4 Multiples of 3: 1,3


Common multiples of 3 and 6?

6,12,18 are the common multiples of 3 and 6


Why are multiples of 6 also multiples of 3?

Because 6 is a multiple of 3.


Do the multiples of 9 are all multiples of 6 and 3?

3 yes, 6 no.


Why are all the multiples of 6 also multiples of 3?

Because 3 is a factor of 6.


What must number 6 have 3 other multiples of?

Multiples of 6 must also be multiples of 1, 2 and 3.


What are the multiples of 3 and 6?

The multiples of 3 are 3, 6, 9, 12, 15, 18, 21 and so on. The first six multiples of 6 are 6, 12, 18, 24, 30, 36, 42 and so on. Common multiples include all the multiples of 6.


Is 18 a common multiples of 3 and 6?

Yes it is... Multiples of 3 & 6 are 3, 6, 9, 12, 15 & 18


How many numbers from 1 to 100 are multiples of 2 3 4 6 8 9?

Assuming you mean that you want the number of multiples of each, then for 1-100: number of multiples of 2 = 50 number of multiples of 3 = 33 number of multiples of 4 = 25 number of multiples of 6 = 16 number of multiples of 8 = 12 number of multiples of 9 = 11 Assuming you mean that you want the numbers that are multiples of 2, 3, 4, 6, 8 or 9, then some numbers may be multiples of more than one (for example 12 is a multiple of 2, 3, 4 and 6) and so a straight addition of the number of multiples of each cannot be done: Consider 2, 4 and 8 Every multiple of 4 or 8 is also a multiple of 2, so all the multiples of 4 and 8 are counted by the multiples of 2. Consider 3 and 9 Every multiple of 9 is also a multiple of 3, so all the multiples of 9 are counted by the multiple of 3 Consider 2, 3 and 6. Every multiple of 6 is an even multiple of 3, so are counted in both the multiples of 2 and 3. So the total number of multiples of 2, 3, 4, 6, 8 or 9 is the number of multiples of 2 plus the number of multiples of 3 minus the number of multiples of 6: For 1 to 100, Number of multiples of 2 = 50 Number of multiples of 3 = 33 Number of multiples of 6 = 16 So number of multiples of 2, 3, 4, 6, 8 or 9 in 1-100 is 50+33-16 = 67. Assuming you mean that they are multiples of all of 2, 3, 4, 6, 8 and 9, then they must be multiples of the lowest common multiple of 2, 3, 4, 6 ,8, 9 2 = 21, 3 = 31, 4 = 22, 6 = 2131, 8 = 23, 9 = 32 LCM = highest power of the primes used = 2332 = 72 Thus all numbers that are multiples of 2, 3, 4, 6, 8 and 9 are multiples of 72, which means between 1 and 100 only 1 number is a multiple of all of them, namely 72


What is the LCM for 6 and 3 and 2?

multiples of 6-6 multiplesof 3- 3,6 multiples of 2- 2,4,6 LCM is 6


Are multiples of 3 also multiples of 6?

Oh, dude, like, totally! If a number is a multiple of 6, it means it can be divided evenly by 6, right? And since 6 is just 3 times 2, any number that's a multiple of 6 is also a multiple of 3. It's like getting two for the price of one, man.