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The first six multiples of 3 are 3, 6, 9, 12, 15, and 18.

Q: What does 6 multiples of 3 mean?

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Multiples of 6 must also be multiples of 1, 2 and 3.

A normal die has two multiples of 3: 3 and 6.

Multiples of 30 from 120 to 990

The one with multiples of 12.

3, 6, 9, 12, 15, 18 4, 8, 12, 16, 20, 24 6, 12, 18, 24, 30, 36 Common multiples include 12, 24, 36, 48, 60, 72

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No; all multiples are not multiples of 6, for example 3×3 = 9 is not a multiple of 6. However as 6 = 2×3 all multiples of 6 are also multiples of 3.

3, 6, 9, 12, 15 The mean is 9.

Multiples of 6: 1,2,3,6 Multiples of 4: 1,2,4 Multiples of 3: 1,3

6,12,18 are the common multiples of 3 and 6

Because 6 is a multiple of 3.

3 yes, 6 no.

Because 3 is a factor of 6.

Multiples of 6 must also be multiples of 1, 2 and 3.

The multiples of 3 are 3, 6, 9, 12, 15, 18, 21 and so on. The first six multiples of 6 are 6, 12, 18, 24, 30, 36, 42 and so on. Common multiples include all the multiples of 6.

Yes it is... Multiples of 3 & 6 are 3, 6, 9, 12, 15 & 18

Assuming you mean that you want the number of multiples of each, then for 1-100: number of multiples of 2 = 50 number of multiples of 3 = 33 number of multiples of 4 = 25 number of multiples of 6 = 16 number of multiples of 8 = 12 number of multiples of 9 = 11 Assuming you mean that you want the numbers that are multiples of 2, 3, 4, 6, 8 or 9, then some numbers may be multiples of more than one (for example 12 is a multiple of 2, 3, 4 and 6) and so a straight addition of the number of multiples of each cannot be done: Consider 2, 4 and 8 Every multiple of 4 or 8 is also a multiple of 2, so all the multiples of 4 and 8 are counted by the multiples of 2. Consider 3 and 9 Every multiple of 9 is also a multiple of 3, so all the multiples of 9 are counted by the multiple of 3 Consider 2, 3 and 6. Every multiple of 6 is an even multiple of 3, so are counted in both the multiples of 2 and 3. So the total number of multiples of 2, 3, 4, 6, 8 or 9 is the number of multiples of 2 plus the number of multiples of 3 minus the number of multiples of 6: For 1 to 100, Number of multiples of 2 = 50 Number of multiples of 3 = 33 Number of multiples of 6 = 16 So number of multiples of 2, 3, 4, 6, 8 or 9 in 1-100 is 50+33-16 = 67. Assuming you mean that they are multiples of all of 2, 3, 4, 6, 8 and 9, then they must be multiples of the lowest common multiple of 2, 3, 4, 6 ,8, 9 2 = 21, 3 = 31, 4 = 22, 6 = 2131, 8 = 23, 9 = 32 LCM = highest power of the primes used = 2332 = 72 Thus all numbers that are multiples of 2, 3, 4, 6, 8 and 9 are multiples of 72, which means between 1 and 100 only 1 number is a multiple of all of them, namely 72

multiples of 6-6 multiplesof 3- 3,6 multiples of 2- 2,4,6 LCM is 6