Nothing. If I is current, V is voltage, and R is resistance, then V=I*R and V*I=P, where P is power.
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One, two, square root of three. M V R equals N H-bar. Rah ! E to the X, D U, D X. Rah ! The NOT of the ORs is the AND of the NOTs. P V equals N R T. The NOT of the ANDs is the OR of the NOTs.
The battery has 6 volts across its terminals. The way to discover it is to apply Ohm's law. It (Ohm's law) comes in 3 "flavors" that look a bit different but all say exactly the same thing. Here they are: E = I x R [Voltage equals current times resistance.] I = E/R [Current equals voltage divided by resistance.] R = E/I [Resistance equals voltage divided by current.] In these equations, voltage is E, current is I and resistance is R. They are measured in units of volts, amperes (or amps) and ohms, respectively. In your problem, we have the resistance (R) and the current (I). We need to find the voltage (E), and the formula E = I x R is the logical choice to discover the voltage. As E = I x R here, E = 0.75 x 8 = 3/4 x 8 = 6 volts. Piece of cake.
power is = V2/R so 40x40= (230)2/R R= 33.25 now V= IR where I is current 230= IXR I= 230/33.25 = 6.9 amp
19 x 4
2 x 3 = 6 x 121.5 = 729