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Let the two numbers be X and Y
Given:
X*Y=75 ==> Y=75/X
X+Y=28
==> X+(75/X)=28
==> X2+75=28X
==> X2-28X+75=0
==> X2-3X-25X+75=0
==> X(X-3)-25(X-3)=0
==> (X-3)(X-25)=0
==> X1-3=0 or X2-25=0
==> X1=3 or X2=25
substitute X1=3 in X+Y=28
3+Y1=28
==>Y1=25
==>Y1=X2
hence the two numbers are 3 and 25
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