No.To check for divisibility by 6, the number must be divisible by both 2 and 3:To check divisibility by 2: if the number is even (last digit is one of 0, 2, 4, 6, 8) then the number is divisible by 2. Last digit of 56 is 6 which is even so 56 is divisible by 2.To check divisibility by 3: if the sum of the digits is divisible by 3, then so is the original number; the test can be repeated on the sum, so if it is repeated until a single digit remains, the original number is divisible by 3 if this single digit is 3, 6 or 9.For 56: 5 + 6 = 11 → 11: 1 + 1 = 2; 2 is not one of 3, 6 or 9, thus 56 is not divisible by 3.As 56 is not divisible by both 2 and 3, it is not divisible by 6.No.We can ask ourselves what are the multiples of six?6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, and so on.We see that 56 is not in this set of numbers. So it's not a multiple of six. We can also see that each of these numbers can be divided by six. So a quicker way of deciding would be to try to divide 56 by 6. 56/6 = 9-4/6 or 9-2/3. It doesn't divide evenly so again, 56 is not a multiple of 6.no60 = 6 x 1054 = 6 x 9so 56 is not a multiple of 6
15 is divisible by 1, 3, 5, 15.
7.5
30 is divisible by: 1, 2, 3, 5, 6, 10, 15, 30.
How about 6, 12, 24, 30...
If the number's last digit is 0, then it is divisible by 10. e.g. 10, 20, 30, 40, 50, 60, 70, 80, 90, 100 and so on are all divisible by ten. but... 45 is not divisible by ten because the last digit is not zero.
The number in question is divisible by 3 and 4.A number is divisible by 3 if the sum of the digits is divisible by 3.A number is divisible by 4 if the last two digits is divisible by 4.963,411,024divisible by 3 because 48 is divisible by 3 and24 is divisible by 4, therefore 12 is a GO!If the number is divisible by both 3 and 4.then the number is then divisble by 12.The divisibility rule for three is to add up all the numbers in the number- if the number is a multiple of three, then the number you started with is divisible by three. Example- 91 you do 9+1=10, so that (91) is not a multiple of three. Extra example- 21 2+1=3 and three is a multiple of three.The divisibility rule for four is one I made myself- That is if the number is even slip it in half or divide by two, once you have done that check if the number is even- If it is, that number is a multiple of four, if not that number is not. Example- 30 30÷2=15 which is not even, so that means that 30 is not a multiple of four. Extra example- 148 148÷2=74 which is even, so 148 is a multiple of four.If the number is divisible by 3 and four, then it is divisible by 12.Divisible by 3-If all of the digits in the number add up to a multiple of three, then that original number is divisible by threeDivisible by 4-If the last two digits in a number are divisible by four, then that original number is divisible by 4.Example: 36Divisible by 3?3+6= 99/3=3, so it is divisible by three.Divisible by 4?Of course, we know that 36 is divisible by 4 (36/9=4)So 36 is divisible by 4Therefore, we know 36 is divisible by 12
Yes, 30 is divisible by 3. 30 divided by 3 is 10.
When one number is divisible by another number, it means that the first number can be divided by the second number without leaving a remainder. In other words, the division operation results in a whole number without any fraction.
composite 3 goes into 3 or 30 3 goes into 9 so 3 goes into 39 13 + 13 + 13 = 39 = 3 x 13 ------------------------------------- Applying a divisibility test: To be divisible by 3, sum the digits of the number and if this sum is divisible by 3, then the original number is divisible by 3. As the test can be repeated on the sum, repeat the summing until a single digit remains; only if this number is one of {3, 6, 9} is the original number divisible by 3. For 39 this gives: 39 → 3 + 9 = 12 12 → 1 + 2 = 3 3 is one of {3, 6,9} so 39 is divisible by 3. As 39 is divisible by 3 (that is 3 is a factor of 39 that is less than 39) and 3 is greater than 1 then 39 is a composite number.
30
30 is divisible by 1, 2, 3, 5, 6, 10, 15, and 30.
No.
No it is not.
30 days
90/3 = 30
No. 80 is not evenly divisible by 30.