21 subtracted by 8.42 = 12.58
125 = 5 x 5 x 5 500 = 2 x 2 x 5 x 5 x 5
Factor them.5 x 5 x 5 x 7 = 8752 x 2 x 2 x 5 x 5 x 5 = 1000Select the common factors.5 x 5 x 5 = 125, the GCF
3 x 5 x 5 x 5 = 375 2 x 2 x 2 x 5 x 5 x 5 = 1000
8-(2x)=10 -(2x)=10-8 -(2x)=2 x=2/(-2) x= -1
4
(x/4)-9=5
19
x-5=10
To find the number that must be subtracted from -5 to get 10, you would set up the equation -5 - x = 10, where x is the unknown number to be subtracted. To solve for x, you would first add 5 to both sides to isolate x, resulting in -x = 15. Then, multiply both sides by -1 to solve for x, giving you x = -15. Therefore, the number that must be subtracted from -5 to get 10 is -15.
The algebraic expression for eleven subtracted from X is: X - 11
13
x/5=-4-2 x=(-6)*5 x=-30 the integer is -30
-11
This can be factored in multiple ways, depending on the signs. X2+10x+25 factors into (x+5)2 or (x+5)(x+5). X2-10x+25 factors into (x-5)2 or (x-5)(x-5). If 25 is being subtracted, then the trinomial is impossible to factor.
54 subtracted by 49 = 5
It is (2x-5)(x-4) when factored