From 96, use 96 and 32. From 49, use 7 and 1 96 + 32 + 7 + 1 = 136
Let's represent the four consecutive whole numbers as n, n+1, n+2, and n+3. The sum of these numbers can be expressed as n + (n+1) + (n+2) + (n+3) = 4n + 6. Given that the sum is 96, we can set up the equation 4n + 6 = 96 and solve for n. Subtracting 6 from both sides gives us 4n = 90, and dividing by 4 gives n = 22.5. However, since n must be a whole number, we can see that this is not a valid solution. Therefore, there are no four consecutive whole numbers that sum up to 96.
7 numbers in a phone number
56 = 2^3 * 7 96 = 2^5 * 3 LCM = 2^5 * 3 * 7 = 32 * 21 = 672
32
7/96 is in its simplest form.
It is n/7.
84.
7 over 8
28/96 = 14/48 = 7/24
7/48
7/12
n/7 = 6+5 n/7 = 11 n = 11 X 7 n = 77
Yes. It can be simplified as 1 and 7 over 48.
7/14 = N/6 7x6=14N 42=14N N=3
7/12 + 3/8 = 92/96 = 23/24
12/13 = 96/104 7/8 = 91/104 96/104 + 91/104 = 187/104 or 1 and 83/104