The LCM of 4, 6, and 16 is 48.
Because 16 is a factor of 48.
48, 96, 144, 192, 240, 288, 336, 384, 432, 480, 528, . . .16, 32, 48, 64, 80, 96, 112, 128, 144, 160, 176, . . .
To simplify the expression 4(-x^2) - 16, first distribute the 4: this results in -4x^2 - 16. Therefore, the simplified expression is -4x^2 - 16.
4, 8, 12, 16, 24, 48
4xz=16
radical(48)/radical(3) = radical(48/3) = radical(16) = 4 Technically, radical(16) is +4 OR -4 but in such questions often only the principal root is required.
c = 4, c squared = 16, 3c squared = 48, 48 + 9 = 57.
The answer is 4 because you multiply both 48 and 12 by the variable (and considering the variable is x) it would equal: 48=12x then you divide both ides by 12 it would equal 4=x the variable equals 4
To write a variable expression for "W increased by 4," you simply take the variable ( W ) and add 4 to it. The expression would be written as ( W + 4 ). This indicates that you are taking the value of ( W ) and increasing it by 4 units.
The lowest common multiple of 16, 3 and 4 is 48. 16 x 3 = 48, 4 x 12 = 48, and 3 x 16 = 48.
The LCM of 16, 48 is 16. This is because 16 =2^4, 48=2^4*3.
The GCF is 4.
The expression ( 16 \div 4 ) is equivalent to ( 4 ). When you divide 16 by 4, you get the result of 4.
The LCM of 4, 6, and 16 is 48.
The expression 2x2x2x2x3 can be simplified by first calculating the product of the fours 2's, which is 2^4 = 16. Then, multiplying that result by 3 gives 16 x 3 = 48. Therefore, 2x2x2x2x3 equals 48.
Substituting a given value for each variable in an algebraic expression involves replacing the variables with specific numbers to evaluate the expression. For example, in the expression (2x + 3y), if (x = 2) and (y = 4), you would replace (x) with 2 and (y) with 4, resulting in (2(2) + 3(4) = 4 + 12 = 16). This process allows you to compute a numerical result from the expression based on the values assigned to its variables.